3 years ago

Michael had 50 chocolates some bullies came by and stole 18 chocolates how much were left

Mathematics

2 answers:

LenKa [72]3 years ago

4 0

I would do it like this,

50-10 =40

40-8= 32

So 58-18 = 32

olya-2409 [2.1K]3 years ago

3 0

Answer: 32

Step-by-step explanation:

50 - 18 = 30

0 - 8

5 becomes 4 and zero becomes 10

10 - 8 = 2

4 - 1 = 3

answer is 32

easy

You might be interested in

Solve each equation for the variable

motikmotik

Answer:

X= -50

Step-by-step explanation:

Remove the parenthesis

multiply both sides by two

x - 6 = -56

Move the 6 to the other side

x = -56 + 6

x = -50

6 0

4 years ago

The book doug is reading is 280 pages long. he has read 84 pages so far. What percent of his book has Doug read

icang [17]

84/280=.3 convert that to a decmal which is 30%

6 0

3 years ago

Read 2 more answers

Plese help me guys !!

Westkost [7]

Answer:option d.

hope it helps you.

3 0

3 years ago

Read 2 more answers

Solve the system by substitution.<br> y = -9x<br> y = 2x + 33

Gwar [14]

Answer:

$y = - 9x \\ theny = 2x + 33 \\ - 9x = 2x + 33 \\ - 9x - 2x = 33 \\ - 11x = 33 \\ x = \frac{ - 33}{11} = - 3 \\ x = - 3 \\then\\ y=-9×-3=21\\ thank \: you$

5 0

3 years ago

The rectangle below has an area of 14x^4 + 6x^2 square meters. The width of the rectangle (in meters) is equal to the greatest c

julia-pushkina [17]

Answer:

$w=2x^2$ and $l = (7x^2+3)$

Step-by-step explanation:

The area of a rectangle is $14x^4+6x^2$ which factors through GCF, by finding the greatest common monomial factor between the two.

$14x^4+6x^2 = 2*7x^4 + 2*3x^2 = 2x^2(7x^2+3)$

The length and width of the rectangle are $w=2x^2$ and $l = (7x^2+3)$ .

7 0

3 years ago