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2 years ago

A child has 4 wooden blocks. How many different ways can she stack 3 of them into a tower?

Mathematics

1 answer:

faltersainse [42]2 years ago

7 0

Answer:

Step-by-step explanation:

To find the number of different ways she can stack 3 of them in a tower, we need to use the formula:

$_{n}P_{k}=\dfrac{n!}{(n-k)!}$

n = 4

k = 3

$_{n}P_{k}=\dfrac{4!}{(4-3)!}$

$_{n}P_{k}=\dfrac{4!}{1!}$

$_{n}P_{k}=\dfrac{4*3*2*1!}{(1)!}$

$_{n}P_{k}=\dfrac{4*3*2*1!}{1}$

$_{n}P_{k}=\dfrac{24}{1}$

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What is the perimeter if X=3 36 24 12 select the correct answer

Korolek [52]

I think the answer is 12 If the perimeter is three

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3 years ago

Read 2 more answers

-1 3/20-2 7/20 plz show work. Negatives and positives

mestny [16]

First you turn both fractions into improper fractions, (-23/20-47/20) then yousubtract the numerator(the top of the fraction) -23-47=-70--> -70/20=7/2. Hope i helped;)

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3 years ago

2.) Fill in the blank.

Montano1993 [528]

Answer:

E.) 1

Step-by-step explanation:

Firstly we will solve for L.H.S.

L.H.S. = $Csc^2\theta$

Since we know that $Csc^2\theta$ is the inverse of $Sin^2\theta$ .

So we can say that;

$csc^2\theta=\frac{1}{sin^2\theta}$

Now For R.H.S.

$Cot^2\theta+1$

Since we can rewrite $cot^2\theta$ as $\frac{cos^2\theta}{sin^2\theta}$ .

Now we can say that the R.H.S. is;

$\frac{cos^2\theta}{sin^2\theta}+1$

Now we add the fraction and get;

$\frac{cos^2\theta+sin^2\theta}{sin^2\theta}$

Now according to trigonometric identity;

$cos^2\theta+sin^2\theta=1$

So, $\frac{cos^2\theta+sin^2\theta}{sin^2\theta}=\frac{1}{sin^2\theta}$

Here,

$csc^2\theta=\frac{1}{sin^2\theta}$ and $Cot^2\theta+1$ = $\frac{1}{sin^2\theta}$

L.H.S. = R.H.S.

Hence $csc^2\theta=cot^2\theta+1$

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2 years ago

Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi

katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 20.8, \sigma = 5.3$