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iren [92.7K]
3 years ago
7

Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π

Mathematics
2 answers:
Luda [366]3 years ago
6 0
4cos2(x)−3=0

or 
4cos2(x)=3

cos(x)= √3/2

π/6, 5π/6,  7π/6,  11π/6



Romashka-Z-Leto [24]3 years ago
5 0
F(x) = 4 [cos (x)]^2 - 3 = 0

4[cos(x)]^2 = 3

cos(x) = √3 / 2

That happens in the first and fourth quadrants, for the angles 30 degrees and 330 degrees.

Answer: x = 30 degrees and x = 330 degrees
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Suppose f(x) = 3x2 – 2x: Find f(-4). А B -40 ОО C 56<br>plz helpp​
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