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4 years ago

when you subtract one negative integer from another, will your answer be greater or less than the integer you started with

1 answer:

6 0

Lets find out...

-5 - (-2) = -5 + 2 = -3....-3 is greater then -5
-1 - (-3) = -1 + 3 = 2.....2 is greater then -1
-4 - (-2) = -4 + 2 = -2...-2 is greater then -4

so it looks like it is going to be greater then the number u started with.

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Please help me fast am stuck<br>

soldier1979 [14.2K]

Answer:

m = 3/2, Option C

Step-by-step explanation:

m = (y2-y1)/(x2-x1)

m = ( -3-(-6))/(0-(-2))

m = 3/2

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3 years ago

What is the quotient of 15p^-4q^-6/-20p^-12q^-3 in simplified form?

musickatia [10]

$\cfrac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}} =\cfrac{3p^{-4+12}}{-4q^{-3+6}} =- \cfrac{3p^{8}}{4q^{3}}$

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3 years ago

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Can anyone answer the questions asked in the picture?

Marina CMI [18]

The greatest number of binders is 5, the greatest number of notebooks is 10. If she buys 7 notebooks then she can only buy 1.

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3 years ago

..vertex: (4, -1)<br> f(3) = -6

s344n2d4d5 [400]

Answer:

$\huge\boxed{f(x)=-5(x-4)^2-1=-5x^2+40x-81}$

Step-by-step explanation:

The vertex form of an equation of a parabola:

$f(x)=a(x-h)^2+k$

$(h;\ k)$ - vertex

We have

vertex $(4;\ -1)\to h=4;\ k=-1$

$f(3)=-6$

Therefore we have:

$f(x)=a(x-4)^2+(-1)=a(x-4)^2-1$

Substitute $x=3$ and $f(3)=-6$

$a(3-4)^2-1=-6\qquad|\text{add 1 to both sides}\\\\a(-1)^2=-6+1\\\\a(1)=-5\\\\a=-5$

Finally:

$f(x)=-5(x-4)^2-1=-5(x^2-2(x)(4)+4^2)-1\\\\=-5(x^2-8x+16)-1=-5x^2+(-5)(-8x)+(-5)(16)-1\\\\=-5x^2+40x-80-1=-5x^2+40x-81$

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3 years ago

If John can repair one machine every 2 hours, write a function h(n) for the hours needed to repair n machines.

aleksley [76]

Answer:

h(n) =2n

Step-by-step explanation:

Hope this helps :)

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3 years ago