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V125BC [204]
3 years ago
12

A standard chemistry examination administered nationally by the American Chemical Society has a mean of 500 and a standard devia

tion of 90. What is the probability that the average of a random sample of examination scores of 25 students will be between 450 and 500?
Mathematics
1 answer:
Maslowich3 years ago
4 0
Let X be a random sample representing the score of a student in the American Chemical Society Examination.
P(450 < x < 500) = P((450 - 500)/(90/sqrt(25)) < z < (500 - 500)/(90/sqrt(25))) = P(-2.778 < z < 0) = P(z < 0) - P(z < -2.778) = P(z < 0) - [1 - P(z < 2.778)] = P(z < 0) + P(z < 2.778) - 1 = 0.5 + 0.99727 - 1 = 0.49727 = 49.7%
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A mean is an arithmetic average of a set of observations. The amount that Jack has to earn in tips on Sunday if he wants to average $19 a day is $25.

<h3>What is Mean?</h3>

A mean is an arithmetic average of a set of observations. it is given by the formula,

\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}

As it is given that Jack makes $12 on Monday, $14 on Tuesday, $18 on Wednesday, $16 on Thursday, $26 on Friday and $22 on Saturday. And we need to know how much he should earn on Sunday, so the average is $19. Therefore, we can write,

\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}

19 = \dfrac{12+14+18+16+26+22+x}{7}\\\\133 = 108 + x\\\\133-108=x\\\\x = 25

Hence, the amount that Jack has to earn in tips on Sunday if he wants to average $19 a day is $25.

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brainly.com/question/16967035

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