All categories

3 years ago

Find the 6th term in the sequence

Mathematics

2 answers:

Dimas [21]3 years ago

6 0

Answer:

C.64

Step-by-step explanation:

The first step is to figure out what the sequence is, the first step is 2, 4 the only ways for 2 to get to 4 would be +2 or *2 so we will look at the next step, 4 to 8. The only ways for 4 to get to 8 is +4 or *2, since these both have *2 in common we will check that with all of the terms

2, 4, 8, 16, 32

2 (*2) = 4 (*2) = 8 (*2) = 16 (*2) 32

Since the equation is working we are going to multiply 32 by 2 to get the 6th term

32 (*2) = 64

tester [92]3 years ago

5 0

Answer:64

Step-by-step explanation:

2+2=4

4+4=8

8+8=16

16+16=32

32+32=64

You might be interested in

Helppp!!!! please!!!.

krek1111 [17]

Answer:

110

Step-by-step explanation:

8 0

4 years ago

HELP WITH ALL <br> Determine the composite functions of the following set of functions

elixir [45]

QUESTION 1

i) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(f\circ g)=f(g(x))$

$(f\circ g)=f(x^2)$

We plug in $x^2$ into $f(x)=5x-2$

$(f\circ g)=5x^2-2$

ii) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(g\circ f)=g(f(x))$

$(g\circ f)=g(5x-2)$

We plug in $5x-2$ into $g(x)=x^2$

$(g\circ f)=(5x-2)^2$

$(g\circ f)=25x^2-10x-10x+4$

$(g\circ f)=25x^2-20x+4$

QUESTION 2

i) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(h\circ g)=h(g(x))$

$(h\circ g)=h(x^2-4)$

We plug in $x^2-4$ into $h(x)=\sqrt{2x+1}$

$(h\circ g)=\sqrt{2(x^2-4)+1}$

$(h\circ g)=\sqrt{2x^2-8+1}$

$(h\circ g)=\sqrt{2x^2-7}$

ii) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{2x+1})$

We plug in $\sqrt{2x+1$ into $g(x)=x^2-4$

$(g\circ h)=(\sqrt{2x+1})^2-4$

$(g\circ h)=2x+1-4$

$(g\circ h)=2x-3$

QUESTION 3

i) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{x-4})$

We plug in $\sqrt{x-4}$ into $g(x)=x+5$

$(g\circ h)=\sqrt{(x-4)+5}$

ii) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ g)=g(g(x))$

$(g\circ g)=g(x+5)$

We plug in $x+5$ into $g(x)=x+5$

$(g\circ g)=(x+5)+5}$

$(g\circ g)=x+10}$

QUESTION 4

The given functions are;

$f(x)=-2x+1$ and $g(x)=-x^2$

$f\circ f=f(f(x))$

$f\circ f=f(-2x+1)$

$f\circ f=-2(-2x+1)+1)$

$f\circ f=4x-2+1)$

$f\circ f=4x-1)$

ii)

$g\circ g=g(g(x))$

$g\circ g=g(-x^2)$

$g\circ g=-(x^2)^2$

$g\circ g=-x^4$

QUESTION 5

$f(x)=5x-2;g(x)=x^2;h(x)=-3x$

$h\circ g\circ f=h\circ (g(f(x))$

$h\circ g\circ f=h\circ (g(5x-2))$

$h\circ g\circ f=h\circ ((5x-2)^2)$

$h\circ g\circ f=h\circ (25x^2-20x+4)$

$h\circ g\circ f=h(25x^2-20x+4)$

$h\circ g\circ f=-3(25x^2-20x+4)$

$h\circ g\circ f=-75x^2+60x-12)$

ii.

$f\circ f\circ g=f\circ (f(g(x))$

$f\circ f\circ g=f\circ (f(x^2)$

$f\circ f\circ g=f\circ (5x^2-2)$

$f\circ f\circ g=f(5x^2-2)$

$f\circ f\circ g=5(5x^2-2)-2$

$f\circ f\circ g=25x^2-10-2$

$f\circ f\circ g=25x^2-12$

7 0

3 years ago

Each person in share's family of 5 eats 3 bowls of cereal each week. Her mother is going grocery shopping and wants to know how

Colt1911 [192]

Y = 5(3x)....y = total number of bowls and x = number of weeks

for 4 weeks......x = 4
y = 5(3*4)
y = 5(12)
y = 60...so the family will eat 60 bowls in 4 weeks

7 0

3 years ago

Read 2 more answers

A rate of 4 centimeters per second is equal to how many meters per hour?

vampirchik [111]

So, let's start with the basics.
One meter is 100 centimeters. Seeing that we have 60 seconds in a minute, and 60 minutes in an hour. The formula would look like this.
(60*60)4
3600*4 = 14400 centimeters
So then we divide it by 100, and
144 meters

4 0

3 years ago

An office has 150 employees, and 30 of the employees work the night shift. What percentage of the employees work the night shift

Zanzabum

<h2>Answer:</h2>

The percent of employees who work in the night shift are:

20%

<h2>Step-by-step explanation:</h2>

Total number of employee in the office are: 150

Number of employee who work in the night shift are: 30

The percent of the employee who work in the night shift is calculated as follows:

$\dfrac{\text{Number\ of\ people\ working\ in\ the\ night\ shift}}{\text{Total\ number\ of\ employees}}\times 100$