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slamgirl [31]
3 years ago
13

How to find the solutions for a quadratic inequality?

Mathematics
1 answer:
viktelen [127]3 years ago
8 0
So if your equation was x squared +2x+1=0 you would do (x+1)(x+1)=0 because 1+1=2(x)
then you do x+1-1=0-1 to check it over
You might be interested in
What is the measurement of the vertex angle of an isosceles triangle if one of its base angles measures 42 degree
kari74 [83]

Hello from MrBillDoesMath!

Answer:

96 degrees


Discussion:

The base angles of an isosceles triangle are equal and a triangle has 180 degrees. In our case this means that


42 + 42 + (measure of vertex angle) = 180

84 + (measure of vertex angle)  = 180 =>     (subtract 84 from both sides)

84 - 84 +  (measure of vertex angle)  = 180- 84 =>  

(measure of vertex angle)  = 180- 84  = 96

Thank you,

MrB

3 0
3 years ago
Convert 15 kg/L to g/mL
geniusboy [140]

Answer: 15g/mL

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help. Approximately how many cubic feet of water does she need?
maria [59]

Answer:

The amount of water she needs to pump in:

V = Base area x Height x 1/2 = (4/2)^2 x pi x 0.75 x 1/2 = 1.5pi = ~4.7 (ft3)

=> Option D is correct.

Hope this helps!

:)

3 0
3 years ago
What’s nine plus ten
natka813 [3]

Answer:

19

Step-by-step explanation:

8 0
3 years ago
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
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