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3 years ago

How to find the solutions for a quadratic inequality?

1 answer:

8 0

So if your equation was x squared +2x+1=0 you would do (x+1)(x+1)=0 because 1+1=2(x)
then you do x+1-1=0-1 to check it over

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HELP PLEASE!!! So for this problem is got 0.48 however I just wanted to confirm that my answer is correct. Can someone please he

densk [106]

Answer:

ur answer is correct

A =xy

A = 1.6×0.3 = 0.48

3 0

4 years ago

Aidan divides a box of crackers evenly among 5 people. If each person gets 7 crackers, how many did he start with? Write and sol

tiny-mole [99]

Answer: x/7=5 or x/5=7

Step-by-step explanation: Well If each person got 7 crackers, and there were 5 people, there were a total of 35 crackers. Division is just multiplication backwards.

6 0

3 years ago

Mr. Singh just left his house to go to work and has a meeting as soon as he arrives. The

vodomira [7]

Answer:5

Step-by-step explanation:

3 0

4 years ago

Ryan wants to plant 1/5 packet of seeds in each row of his garden. He has 4 packets of seeds. Ryan used the expression 1/5 divid

mel-nik [20]

Answer:

Ryan should have done 1/5*4 instead of 1/5 divided by 4.

6 0

3 years ago

Read 2 more answers

A men’s softball league is experimenting with a yellow baseball that is easier to see during night games. One way to judge the e

vodomira [7]

Answer:

Yes. There is enough evidence to support the claim that there are fewer errors on average when the yellow ball is used.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The sample data is:</em>

Yellow 5 2 6 7 2 5 3 8 4 9

White 7 6 8 5 9 11 8 3 6 10

This is a hypothesis test for the difference between populations means.

The claim is that there are fewer errors on average when the yellow ball is used.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2< 0$

The significance level is α=0.05.

The sample 1 (yellow ball errors), of size n1=10 has a mean of 5.1 and a standard deviation of 2.42.

The sample 2 (white balls errors), of size n2=10 has a mean of 7.3 and a standard deviation of 2.41.

The difference between sample means is Md=-2.2.

$M_d=M_1-M_2=5.1-7.3=-2.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{2.42^2+2.41^2}{10}}\\\\\\s_{M_d}=\sqrt{\dfrac{11.665}{10}}=\sqrt{1.166}=1.08$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-2.2-0}{1.08}=\dfrac{-2.2}{1.08}=-2.037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=10+10-2=18$

This test is a left-tailed test, with 18 degrees of freedom and t=-2.037, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.028) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that there are fewer errors on average when the yellow ball is used.

3 0

4 years ago