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3 years ago

How to find the solutions for a quadratic inequality?

1 answer:

8 0

So if your equation was x squared +2x+1=0 you would do (x+1)(x+1)=0 because 1+1=2(x)
then you do x+1-1=0-1 to check it over

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I need help for number 5

yKpoI14uk [10]

Answer: 1

Step-by-step explanation:

8 0

3 years ago

3) Which ordered pair in the form (x, y) is a solution of this equation?<br> 7x - 5y = 1

Ludmilka [50]

(x,y) = (1, 1.2)
1 = 7(1) - 5(1.2)
1 = 7 - 6

There are many other options though.

3 0

3 years ago

The side lengths of the following right triangle 15,20 and 25, as shown below. The altitude from the right angle splits the hypo

kompoz [17]

Answer:

$h = 12$

$x = 9$

$y= 16$

Step-by-step explanation:

Given

The attached triangle

Required

Find h, x and y

Let the base of the triangle be 15.

So, the area is:

$A = \frac{1}{2} * 15 * 20$

$i.e\ height = 20$

$A = \frac{1}{2} * 300$

$A = 150$

Let the base of the triangle be 25.

So, the area is:

$A = \frac{1}{2} * 25 * h$

$i.e\ height = h$

$A = \frac{1}{2} * 25h$

Substitute $A = 150$

$\frac{1}{2}*25h = 150$

Solve for h

$h = \frac{150 *2}{25}$

$h = 6 *2$

$h = 12$

Considering the smallest triangle

$Hypotenuse = 15$

So:

$15^2 = h^2 + x^2$

$15^2 = 12^2 + x^2$

This gives:

$15^2 - 12^2 = x^2$

$81 = x^2$

Take square roots

$9 =x$

$x = 9$

Solving for y

$x + y = 25$

$y= 25 - x$

$y= 25 - 9$

$y= 16$

7 0

3 years ago

A rectangular region is removed from another rectangular region to create the shaded region shown below. Find the area of the sh

Mila [183]

Answer:

Step-by-step explanation:

Area of bigger rectangle (A1)= 9×11=99

Area of smaller rectangle(A2)=8×6=48

Area of shaded region(A)=99-48=52

6 0

3 years ago

How do I solve this problem

tino4ka555 [31]

Answer:

0.6

Step-by-step explanation:

2x3 add 1 power of 10 to the 3 you get 6 and now you just remove/divide the power of 10 you added and you get .6

7 0

3 years ago