Hey can you please help me posted picture of question :)
2 answers:
Answer:
The solutions are -3 and -6
Explanation:
First we would need to put the equation in standard form which is:
ax² + bx + c = 0
This can be done as follows:
x² + 18 = -9x
x² + 9x + 18 = 0
By comparison, we would find that:
a = 1
b = 9
c = 18
Now, to get the roots, we would use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x =
or x =
Hope this helps :)
The solutions are -3 and -6
Explanation:
First we would need to put the equation in standard form which is:
ax² + bx + c = 0
This can be done as follows:
x² + 18 = -9x
x² + 9x + 18 = 0
By comparison, we would find that:
a = 1
b = 9
c = 18
Now, to get the roots, we would use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x =
or x =
Hope this helps :)
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Answer:
The equation of the line is y - 3 = -2(x + 4)
Step-by-step explanation:
* Lets explain how to solve the problem
- The slope of the line which passes through the points (x1 , y1) and
(x2 , y2) is
- The product of the slopes of the perpendicular lines = -1
- That means if the slope of a line is m then the slope of the
perpendicular line to this line is -1/m
- The point-slope of the equation is
* lets solve the problem
∵ A given line passes through points (-4 , -3) and (4 , 1)
∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1
∴ The slope of the line
- The slope of the line perpendicular to this line is -1/m
∵ m = 1/2
∴ The slope of the perpendicular line is -2
- Lets find the equation of the line whose slope is -2 and passes
through point (-4 , 3)
∵ x1 = -4 , y1 = 3
∵ m = -2
∵ y - y1 = m(x - x1)
∴ y - 3 = -2(x - (-4))
∴ y - 3 = -2(x + 4)
* The equation of the line is y - 3 = -2(x + 4)