Answer: B. Funds need to be easily accessible
This is so you can access it easily without paying a penalty
The question says that the length of the floor of a room is 'y' meters.
Its width is 5 meters shorter than the length,
If the width is 5 meters shorter than the actual width should be:
meters
Now the room is in the shape of a rectangle, so we will use the formula of the perimeter of a rectangle:
Perimeter =
The length of the floor is 'y' meters
The width of the floor is 'y-5' meters
Plugging the values of length and width we get,
![2(y+ (y-5))](https://tex.z-dn.net/?f=2%28y%2B%20%28y-5%29%29)
Question says that the perimeter of the rectangle is
meters.
So,
![2(y+(y-5))=4y+1](https://tex.z-dn.net/?f=2%28y%2B%28y-5%29%29%3D4y%2B1)
We will solve for 'y'.
![2(y+y-5)=4y+1](https://tex.z-dn.net/?f=2%28y%2By-5%29%3D4y%2B1)
![2(2y-5)=4y+1](https://tex.z-dn.net/?f=2%282y-5%29%3D4y%2B1)
![4y-10=4y+1](https://tex.z-dn.net/?f=4y-10%3D4y%2B1)
Since,
![-10\neq 1](https://tex.z-dn.net/?f=-10%5Cneq%201)
The system of equation seems to have no solution.
Hence, no such floor exists.
X/5 > -2
Multiply 5 on both sides:
x > -10
Draw a graph and draw a line for x > -10
(Look at the attachment below - where the green line is shown make it dotted)
Hope it helped :)