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qaws [65]
3 years ago
14

Whats (0,5), m=1/3 in point-slope form

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0
Y-5 = (1/3)(x)

You can look at Khan Academy for how to write an equation in point-slope form but I think it's pretty self explanatory.

y - (the y value in the point) = (slope)*(x - (the x value in the point))


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I spent 3/4 of my money and then I spent 1/5 of what was left.
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(3/4)+(1/5(1/4)

As my thinking, this is the answer...

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Directions:Use the product rule to simplify the following monomials.
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Answer:

See answers below

Step-by-step explanation:

6) -12(a^5)(b^6)

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600/99 in simplest form
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Step-by-step explanation:

8 0
4 years ago
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Inverse laplace of L^-1 {5s/s^2 + 3s - 4}​
Salsk061 [2.6K]

Answer:

e^t+e^{-4t}

Step-by-step explanation:

We have to simplify the original function using partial fraction, hence:

\frac{5s}{s^2+3s-4} =\frac{5s}{(s-1)(s+4)}\\\\=\frac{A}{s-1}+\frac{B}{s+4}\\\\Therefore:\\\\\frac{A(s+4)+B(s-1)}{(s-1)(s+4)}=\frac{5s}{(s-1)(s+4)}\\\\Eliminating\ the \ denominator:\\\\A(s+4)+B(s-1)=5s\\\\substitute\ s=1:\\\\A(1+4)+B(1-1)=5(1)\\\\5A=5\\\\A=1\\\\tsubstitute\ s=-4:\\\\A(-4+4)+B(-4-1)=5(-4)\\\\-5B=-20\\\\B=4\\\\Therefore\ substituting\ A\ and\ B\ gives:\\\\\frac{5s}{s^2+3s-4}=\frac{1}{s-1}+ \frac{4}{s+4}\\\\

From\ Laplace\ inverse:\\\\But\ L^{-1}[\frac{1}{s-a} ]=e^{at}\\\\Hence:\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=L^{-1}[\frac{1}{s-1} ]+L^{-1}[\frac{4}{s+4} ]=e^{t}+4e^{-4t}\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=e^{t}+4e^{-4t}

5 0
3 years ago
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