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Jlenok [28]
3 years ago
11

Use the expression - 8( - 2.5-7).

Mathematics
1 answer:
Paladinen [302]3 years ago
6 0

Answer:

20+56 or basically 76

Step-by-step explanation:

Just multiply -8 to -2.5 and -7.

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Sophia spent $27.16 on four sandwiches. If each sandwich cost the same amount, how much does one sandwich cost?
HACTEHA [7]

Answer:

6.79

Step-by-step explanation:

you just divide 27.16 (the cost) by 4 (how many sandwiches were purchased)

5 0
2 years ago
What is a fraction eqivalent to 5/6​
BaLLatris [955]

Answer:

10/12 is an eqivalent fraction to 5/6 hope this helps

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the slope of the line?
LenKa [72]

Answer:

-3/4

Step-by-step explanation:

Option 1

Direction of the line: Down

-Negative Slope

Rise=-3

Run=4

Rise/Run=-3/4

Option 2

Points: (1,-2) and (-3,1)

y2-y1/x2-x1= 1-(-2)/-3-1

1+2/-3-1

-3/4

3 0
3 years ago
Read 2 more answers
3721nm equals how many m
e-lub [12.9K]

Answer:

0.000003721m

Scientific Notation: 3.72*10^-6

Step-by-step explanation:

1nm is 1*10^-6nm

Based on that we find the answer above.

8 0
2 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
2 years ago
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