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Natalija [7]
3 years ago
7

What ordered pairs are on the graph of 7x-y=2

Mathematics
1 answer:
Mademuasel [1]3 years ago
3 0

Answer:

(0,-2) (2/7,0)

Step-by-step explanation:

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(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]

Answer:

<h2>5</h2>

Step-by-step explanation:

Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.

On expanding the left hand side of the expression we have;

= (8x² −15x)−(x² −27x)

Open the paranthesis

= 8x² −15x−x²+27x

collect the like terms

= 8x²−x²+27x −15x

=  7x²+12x

Comparing the resulting expression with ax²+bx

7x²+12x =  ax²+bx

7x² = ax²

a = 7

Also;

12x = bx

b =12

The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a is equivalent to 5

3 0
3 years ago
Thank you for helping me
dedylja [7]

Answer:

thank you for giving me points ;)

Step-by-step explanation:

4 0
3 years ago
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Compare. Use &gt;, &lt;, or = to complete the statement. | –10 | | 11 | A. &gt; B. = C. &lt;
mash [69]
Answer: |-10| < |11|

So choice C. is right.

hope this helps!
6 0
3 years ago
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Evaluate the following expressions log^6 6
lys-0071 [83]

\bf \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\stackrel{\textit{let's use this one}}{\downarrow }}{log_a a^x = x}\qquad \qquad a^{log_a x}=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ log_6(6)\implies log_6(6^1)\implies 1

7 0
3 years ago
PLEASE HELP 2x^2-8x+6=0
aalyn [17]

Answer:

x = 4 or x = -1

Step-by-step explanation:

2x^2 - 8x + 6 =0

divide by 2 we get  : x^2 -4x +3 = 0

(x -4) (x+1)

x = 4 or x = -1

7 0
3 years ago
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