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3 years ago

What is 1 1/3 as a improper fraction

1 answer:

8 0

Okay so for this all you have to do is add 1 to 1/3.

However, to do this you first need to convert 1 into a fraction.

1 = 3/3
3/3 + 1/3 = 4/3

Hope this helps :)

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Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr

dybincka [34]

Answer:

$\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}$

Step-by-step explanation:

$\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}$

The applicable rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a/b) = log(a) -log(b)

log(a^b) = b·log(a)

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3 years ago

Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

otez555 [7]

We can write the function in terms of y rather than h(x) so that:

y = 3 (5)^x

A. The rate of change is simply calculated as:

r = (y2 – y1) / (x2 – x1) where r stands for rate

Section A:

rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)

rA = 12

Section B:

rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)

rB = 300

B. We take the ratio of rB / rA:

rB/rA = 300 / 12

rB/rA = 25

So we see that the rate of change of section B is 25 times greater than A

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3 years ago

Given AB intersects DE at point C. prove: DCB = ECA. What is the missing reason in step 5

kicyunya [14]

Answer: the answer is linear pair

Step-by-step explanation:

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3 years ago

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Stels [109]

Answer:

$\large\boxed{V=366.16\pi\ ft^3}$

Step-by-step explanation:

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3 years ago

Write as a fraction in simplest form.

seropon [69]

Answer:

2/4=1/2

3/6=1/2

4/16=1/4

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2 years ago