Write an equation for a horizontal line that passes that (4, -2)

The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0

STatiana [176]

Answer:

The marginal-revenue equation is $R'(x)=0.1226x+1.1584$ .

The marginal revenue for the production of 200,000,000 bushels is $R'(x)=1.4036$ .

The marginal revenue for the production of 650,000,000 bushels is $R'(x)=9.1274$ .

Step-by-step explanation:

The derivative $R'(x)$ of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, $R(x) = 0.0613x^{2} +1.1584x+2.4813$ . Therefore, the marginal revenue function is

$R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584$

To find the marginal revenue for the production of:

200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036$

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274$

3 0

3 years ago

What is 4+56+8474+7883939+7494equal

julia-pushkina [17]

4+56+8474+7883939+7494 is equal to 7899967

8 0

4 years ago

Read 2 more answers

What is the graph for y=-3x-2

Korolek [52]

Answer:

Below is the graph which answers your question. Hopefully this helps :)

Mark me the brainliest ♤♤

4 0

4 years ago

Please Evaluate <br> 9[y^3(z-6)-5] for y=2 and z=8

mafiozo [28]

I believe the answer would be 99

plug in the variables and solve to answer this question.

3 0

3 years ago

Read 2 more answers

Both questions please

Nataly [62]

Let there be $h$ 50 cent coins (call them halfs), $d$ 10 cent coins (dimes) and $n$ 5 cent coins (nickles).

81 coins:

$h+d+n=81$

Three more dimes than halfs:

$d=h+3$

Nickels are twice halfs plus dimes:

$n=2(h+d)$

Three equations in three unknowns. We'll eliminate $n$ first:

$n=81-(h+d)=2(h+d)$

$81=3(h+d)$

$h+d=27$

Substituting $d=h+3$

$h+h+3=27$

$2h=24$

$h=12$

$d=h+3=15$

$n=2(h+d)=2(27)=54$

Check we have the right number of coins:

$h+d+n=12+15+54=81 \quad\checkmark$

Good. The amount of money is

$50h+10d+5n=0.50(12)+0.10(15)+0.05(54)=\$10.20$

Part 2.

a for amount Tim gave cousin. Initially Tim has $146.65, cousin $10.55

After he gave the money Tim had twice as much:

$146.65 - a = 2(10.55 + a)$

$146.65 - a = 21.10 + 2a$

$146.65 - 21.10 = 3a$

$a = \dfrac{146.65 - 21.10}{3}= 41.85$

That's the answer to b. After the transfer the cousin has $10.55+41.85=\$52.40$

4 0

3 years ago