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kolezko [41]
3 years ago
15

What is the solution to the inequality? 17 < 9 + x

Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

Answer:

x > 8

Step-by-step explanation:

Given

17 < 9 + x ( subtract 9 from both sides )

8 < x , hence

x > 8

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10 because she already knows 3 so then you divide 80 (number of words she hasn’t learned) by 8 (the number of weeks) and you get 10.
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If sinx = p and cosx = 4, work out the following forms :<br><br><br>​
Kay [80]

Answer:

$\frac{p^2 - 16} {4p^2 + 16} $

Step-by-step explanation:

I will work with radians.

$\frac {\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)} {[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]}$

First, I will deal with the numerator

$\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)$

Consider the following trigonometric identities:

$\boxed{\cos\left(\frac{\pi}{2}-x \right)=\sin(x)}$

$\boxed{\sin\left(\frac{\pi}{2}-x \right)=\cos(x)}$

\boxed{\sin(-x)=-\sin(x)}

\boxed{\cos(-x)=\cos(x)}

Therefore, the numerator will be

$\sin^2(x)-\sin(x)-\cos^2(x)+\sin(x) \implies \sin^2(x)- \cos^2(x)$

Once

\sin(x)=p

\cos(x)=4

$\sin^2(x)-\cos^2(x) \implies p^2-4^2 \implies \boxed{p^2-16}$

Now let's deal with the numerator

[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]

Using the sum and difference identities:

\boxed{\sin(a \pm b)=\sin(a) \cos(b) \pm \cos(a)\sin(b)}

\boxed{\cos(a \pm b)=\cos(a) \cos(b) \mp \sin(a)\sin(b)}

\sin(\pi -x) = \sin(x)

\sin(2\pi +x)=\sin(x)

\cos(2\pi-x)=\cos(x)

Therefore,

[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)] \implies [\sin(x)+\cos(x)] \cdot [\sin(x)\cos(x)]

\implies [p+4] \cdot [p \cdot 4]=4p^2+16p

The final expression will be

$\frac{p^2 - 16} {4p^2 + 16} $

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3 years ago
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Cloud [144]

Answer:

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Step-by-step explanation:

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The submarine is at an elevation of -3552/7 feet
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The answer to your problem is just through simple calculation.

Answer: -507.428571

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function travelSpeed = CalculateTravelSpeed(startX, startY, endX, endY, travelTime) % startX, startY: Starting coordinates % end
Ilia_Sergeevich [38]

Answer:

The functions in Python is as follows:

from math import *

def CalculateTravelSpeed(startX,startY,endX,endY,travelTime):

   travelSpeed = EuclideanDist(startX, startY, endX, endY) / travelTime

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def EuclideanDist(startX, startY, endX, endY):

   dist = sqrt((startX - endX)**2 + (startY - endY)**2)

   return dist

Step-by-step explanation:

from math import *

This defines the CalculateTravelSpeed function

def CalculateTravelSpeed(startX,startY,endX,endY,travelTime):

This calls the EuclideanDist function to calculate the distance; Next, the speed is calculated

   travelSpeed = EuclideanDist(startX, startY, endX, endY) / travelTime

This returns the calculated speed

   return travelSpeed

This defines the EuclideanDist function

def EuclideanDist(startX, startY, endX, endY):

This calculates the distance from the given coordinates

   dist = sqrt((startX - endX)**2 + (startY - endY)**2)

This returns the calculated distance

   return dist

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