Answer:
$19.35
Step-by-step explanation:
Answer: 4(3-t)(3+t)
Step-by-step explanation:
after you find the GCF you will have 4(9-t) squared. since 9 is square you will after to put the square root of 9 (which is 3) into the equation when you factor it further. therefore giving you 4(3-t)(3+t). if you un- factored your equation you would get 4(81-t) because 9x9 is 81 not 3. hope this helps. just learned this too lol
The probability that a participant successfully catches 3 rainbow trout, given that the participant was a woman is 0.0042.
P(woman) = 12/28
= 3/7
P(men) = 16/28
= 4/7
P(3 trouts) = P(3 trout | women)*P(woman) + P(3 trout | men)*P(man)
= P(3 trout | women)*(3/7) + (15C3 * (0.09^3)*(1-0.09)^(15*3))*(4/7)
= P(3 trout | women)*(3/7) + (0.00476)*(4/7)
P(woman | 3 trout) = P(3 trout | women)*P(woman) / P(3 trouts)
{P(3 trout | women) = p}
p*(3/7) / (p*(3/7) + (0.00476)*(4/7)) = 0.40
p*(3/7)/0.40 = (p*(3/7) + (0.00476)*(4/7))
p*((3/7)/0.40 - (3/7)) = (0.00476)*(4/7)
p = [(0.00476)*(4/7)] / [((3/7)/0.40 - (3/7))]
= 0.0042
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The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
In the question ,
it is given that
the time taken to vacate the stadium = 20 minutes
number of exits = 25 exits
capacity of the stadium = 25000 spectators .
given that ,
time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .
time taken ∝ number of spectators ∝ 1/number of exits .
to remove the proportionality sign , we write the constant
time taken = k * (number of spectators)/(number of exits) .
20 = k * 25000/25
20 = k * 1000
k = 20/1000
k = 2/100
k = 1/50 = 0.02
So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula
time taken = (0.02)*(21000/15)
= 0.02*1400
= 28
Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
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