The slope of the line can be defined as y = mx + b, where m is the slope
To find the slope, one will need to use the expression Δy/Δx (y final - y initial)/(x final - x initial)
For this problem, that equals 1/3
Now we will use the point slope form
(y - y initial) = m (x - x initial):
y + 1 = 1/3 (x - 2)
y = 1/3x - 5/3
Answer:
3x + 2x2 + 4 = 5
3x + 2x2 + 4 – 5 = 5 – 5
First be sure that the right side of the equation is 0. In this case, all you need to do is subtract 5 from both sides.
3x + 2x2 – 1 = 0
2x2 + 3x – 1 = 0
Simplify, and write the terms with the exponent on the variable in descending order.
2x2
+
3x
–
1
=
0
↓
↓
↓
ax2
bx
c
a = 2, b = 3, c = −1
Now that the equation is in standard form, you can read the values of a, b, and c from the coefficients and constant. Note that since the constant 1 is subtracted, c must be negative.
Answer
2x2 + 3x – 1 = 0; a = 2, b = 3, c = −1
Step-by-step explanation:
Answer:
15 days
Step-by-step explanation:
Don't you mean 1/3? If so,
5 cans
-------------------- = 15 days
1/3 can/daily
Answer:
<u>Given</u>
- tanθ = 3.454
- θ is in the III quadrant
We know in the III quadrant both sine and cosine are negative.
<u>Use the following identities to get values of sinθ and cos θ</u>
- sinθ = - tanθ/√(1 +tan²θ)
- cosθ = - 1/√(1 +tan²θ)
<u>Substitute the value of tanθ and find sine and cosine:</u>
- sinθ = - 3.454/√(1 + 3.454²) = - 0.961
- cosθ = - 1/√(1 + 3.454²) = - 0.278
Answer: 50.85
hope it helps and I need brainliest and thanks to get to the next level
