You need to work backwards
if it is no more than 9 units away from 8
thus x must be 8-9<x<8+9 solving -1<x<17
so the answer is 4.
90 degrees
the diagonals intersect at right angles
Out of 3 coins, if you are given that 1 is on tails, then the most heads you could have is 3 coins - 1 tails = 2 heads.
The probability of getting 3 heads would be 0.
P(defective) = 3/12 = 1/4
P(good) = 1 - 1/4 = 3/4



The probability that at least 2 units are good is given by:
P(2 good) + P(3 good) + P(4 good) = 0.211 + 0.422 + 0.316 = 0.949.
X7,y2 i don’t know what else to thing