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madreJ [45]
2 years ago
14

What is the tenth term in the sequence 5,8,11,14...? A. 29 B.32 C. 35 D. 38

Mathematics
2 answers:
Mademuasel [1]2 years ago
4 0
Since the sequence is adding 3 to each number, 5+3=8, 8+3=11, 11+3=14, 14+3=17, 17+3=20, 20+3=23, 23+3=26, 26+3=29, 29+3=32, 32 is the answer since it is the tenth term in sequence.
Andrej [43]2 years ago
3 0
Cause 5+3+8, 8+3=11 11+3=14, so 14+3=17 17+3=20, 20+3=23 23+3=26 26+3=29 29+3=32
so its 5, 8, 11, 14, 17, 20, 23, 26, 29, 32
so the answer is 32
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Solve for x using the quadratic formula x^2-6x +9=0
Rufina [12.5K]

Answer:

3 both ways x = 3

EXPLANATION:

plug in inputs and do a little simplifying we get

x = 6 ± √(36-36) all of that over 2

So we simplify and we get 6±sqrt(0) / 2

Then we get 6/2 = 3

x-0 = x+0

thats why there is only one answer

4 0
3 years ago
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Find the LCM of 8, 12, and 26
Dafna1 [17]
312 is the LCM for this set
3 0
3 years ago
Work out the area of a parallelogram of base 6cm and height 8cm
trapecia [35]
The formula to find the area of a parallelogram is: A=bh (b standing for your base, and h for height) You substitute 6 and 8 into your formula and your answer is 48cm^{2}
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3 years ago
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solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
2 years ago
It’s MATH who knows how to do this i’m down bad
AysviL [449]

Answer/Step-by-step explanation:

1. 7x + 2 = 5x + 22 (alternate interior angles are congruent)

Collect like terms

7x - 5x = -2 + 22

2x = 20

2x/2 = 20/2

x = 10

2. 13x - 6 = 10x + 24 (alternate interior angles are congruent)

Collect like terms

13x - 10x = 6 + 24

3x = 30

3x/3 = 30/3

x = 10

3. (12x + 26)° + 46° = 180° (same side interior angles are supplementary)

12x + 26 + 46 = 180

12x + 72 = 180

12x + 72 - 72 = 180 - 72

12x = 108

12x/12 = 108/12

x = 9

4. (5x + 5)° + 135° = 180° (same side interior angles are supplementary)

5x + 5 + 135 = 180

5x + 140 = 180

5x + 140 - 140 = 180 - 140

5x = 40

5x/5 = 40/5

x = 8

4 0
3 years ago
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