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lina2011 [118]
3 years ago
10

Solve for W

Mathematics
2 answers:
umka2103 [35]3 years ago
4 0

In this equation w = -1.1

In order to find this, get all w values to the right side and all numbers to the left side.

-2.27 + 9.1w + 1.3w = -3.4w - 17.45 ----> combine like terms

-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides

-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides

13.8w = -15.18 -----> divide both sides by 13.8

w = -1.1

kondaur [170]3 years ago
4 0

-2.27 + 9.1w + 1.3w = -3.4w - 17.45

First, combine like terms

-2.27 + (9.1w + 1.3w) = -3.4w - 17.45

-2.27 + 10.4w = -3.4w - 17.45

Add 2.27 to both sides and 3.4w to both sides to isolate the w.

-2.27 (+2.27) + 10.4w (+3.4w) = -3.4w (+3.4w) - 17.45 (+2.27)

10.4w + 3.4w = -17.45 + 2.27

Simplify

13.8w = -15.18

Isolate the w. Divide 13.8 from both sides

13.8w/13.8 = -15.18/13.8

w = -15.18/13.8

w = -1.1

-1.1 should be your answer

hope this helps

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5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0    and      x - 3m = 0

⇒ (x - m)(x - 3m) = 0

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**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

  • Bigger non-shaded Δ: L = 12-x, w = 10  ⇒ A = \dfrac{10(12-x)}{2}
  • Smaller non-shaded Δ: L = x, w = x ⇒ A=\dfrac{x(x)}{2}

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}

Area of ΔBEF:

\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18

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