How many ways are there to arrange 7 distinct red and 5 distinct blue balls in a row such that no two blue balls are next?
2 answers:
You might be interested in
See the image for details
Answer:
The correct option is (B) Fail to reject the null hypothesis with either α = .05 or α = .01
Step-by-step explanation:
Consider the provided information.
The size of sample 1 = n1 = 10
The size of sample 2 = n2 = 10
It is given that the test statistic is: t = 2.095
For α = 0.05
ndf = n1 + n2 - 2
Substitute the respective values in the above formula.
ndf = 10 + 10 - 2 = 18
Two Tailed Test:
From the table, critical value of t = 2.1009
But the calculated value of t = 2.095 which is less than critical value of t = 2.1009, Fail to reject .
For α = 0.01
From the table, critical value of t = 2.8784
But the calculated value of t = 2.095 which is less than critical value of t = 2.8784, Fail to reject .
Hence, the correct option is (B) Fail to reject the null hypothesis with either α = .05 or α = .01