Question

What is the area of a triangle whose side is 17 meters long​

Answer 1

Answer:

125.141

Step-by-step explanation:

Assuming that this is an equilateral triangle, I am going to divide this triangle in half to get a right triangle.

17 is our hypotenuse

17/2 = 8.5, this is one of our legs

The other leg is our height, which we will find.

We use Pythagoras Theorem to find the height/leg: $a^{2} +b^{2} =c^{2}$

$17^{2} -8.5^{2} = 216.75$

$\sqrt{216.75}$ = 14.72243186

Now, we use another formula to find the area of the triangle: $\frac{Base*Height}{2}$

14.72243186 × 17 = 250.2813416

250.2813416 ÷ 2 = 125.1406708