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Sliva [168]
3 years ago
10

WILL AWARD BRAINLIEST

Mathematics
1 answer:
stepan [7]3 years ago
4 0

Answer:

1. a. 3xy²(7x²y³ + 5x - 4y)

2. a. (3x + 2)(5x + y)

3. d. (2a + b)(5x - 4)

Step-by-step explanation:

For #1, your answer was missing an exponent, which I boldfaced. Every term has a <em>y</em><em>²</em><em> </em>in common. Then, in numbers 2 and 3, just factor each group one at a time.

Ex: [10ax + 5bx] - [8ay - 4by]

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2 years ago
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What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
atroni [7]

Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

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(x + 3)^2 - 9 + (y - 1)^2 -1 = 3.  Move the constants -9 and -1 to the other side of the equation:  (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13

Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


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2 years ago
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