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3 years ago

How to solve y=x-1 2x-y=0

2 answers:

7 0

Solve the following system:
{y = x - 1 | (equation 1)
{2 x - y = 0 | (equation 2)

Express the system in standard form:
{-x + y = -1 | (equation 1)
{2 x - y = 0 | (equation 2)

Swap equation 1 with equation 2:
{2 x - y = 0 | (equation 1)
{-x + y = -1 | (equation 2)

Add 1/2 × (equation 1) to equation 2:
{2 x - y = 0 | (equation 1)
{0 x+y/2 = -1 | (equation 2)

Multiply equation 2 by 2:
{2 x - y = 0 | (equation 1)
{0 x+y = -2 | (equation 2)

Add equation 2 to equation 1:
{2 x+0 y = -2 | (equation 1)
{0 x+y = -2 | (equation 2)
Divide equation 1 by 2:
{x+0 y = -1 | (equation 1)
{0 x+y = -2 | (equation 2)
Collect results:
Answer: {x = -1
{y = -2

kari74 [83]3 years ago

6 0

Hello there!

y = x - 1
2x - y = 0

We need to solve y = x - 1 for y

Start by substituting x - 1 for y in 2x - y = 0

2x - y = 0

2x - (x - 1) = 0

2x - x + 1 = 0

x + 1 = 0

x = 0 - 1

x = -1

We can use the value of x to find the value for y

Substitute -1 for x in y = x - 1

y = x - 1

y = -1 - 1
y = -2

The answers are: x = -1 and y = -2

I hope you understand the steps and if you have any questions about the answer, just let me know.

As always, I am here to help you!

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Answer:

(14.1, 14.1)

Step-by-step explanation:

If the point (x,y) is on the line y=x, then it has coordinates (x,x).

Find the distances from this point to points (-6,2) and (10,-9):

distance from (x,x) to (-6,2): $\sqrt{(x-(-6))^2+(x-2)^2}=\sqrt{(x+6)^2+(x-2)^2}$
distance from point (x,x) to (10,-9): $\sqrt{(x-10)^2+(x-(-9))^2}=\sqrt{(x-10)^2+(x+9)^2}$

Equate these distances:

$\sqrt{(x+6)^2+(x-2)^2}=\sqrt{(x-10)^2+(x+9)^2}$

Square this equation:

$(x+6)^2+(x-2)^2=(x-10)^2+(x+9)^2\\ \\x^2+12x+36+x^2-4x+4=x^2-20x+100+x^2+18x+81\\ \\8x+40=-2x+181\\ \\8x+2x=181-40\\ \\10x=141\\ \\x=14.1$

So, the coordinates are (14.1, 14.1)

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4 years ago

Multiplying/dividing signs with the same sign will give you what sign in your anwser

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Step-by-step explanation:

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3 years ago

You have $25 to spend on picking 21 pounds of three different types of apples in an orchard. The Empire apples cost $1.40 a

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Answer:

5 pounds of the Empire apples, 14 pounds of the Red Delicious apples, and 2 pounds of the Golden Delicious apples.

Step-by-step explanation:

Let's call the Empire apples weight at E, the Red Delicious at R, and the Golden Delicious at G. We know that the total weight must be 21 pounds so:

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The total amount of spent must be $25, and the price given is per pound, so the priced paid is the cost multiplied by the weight:

1.40*E + 1.10*R + 1.30*G = 25 (equation 2)

And the weight of the Red Delicious must be equal to twice of the combined weight of the others:

R = 2*(E + G)

E + G = R/2 (equation 3)

Let's substitute equation 3 in equation 1

R + R/2 = 21

(2R + R)/2 = 21

3R = 42

R = 14 pounds.

So, E + G = 7

G = 7 - E (equation 4)

Let's substitute the result of R and the equation 4 in the equation 2:

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Answer:

SSS congruency theorem ⇒ 3rd answer

Step-by-step explanation:

* Lets revise the cases of congruent

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- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

leg of the 2nd right angle Δ

* Lets complete the missing

- Given: AB ≅ CD and AD ≅ BC

- Prove: ABCD is a parallelogram

* Statements Reasons

1. AB ≅ CD ; AD ≅ BC given

2. AC ≅ AC reflexive property

3. △ ADC ≅ △ CBA SSS congruency theorem

- The three sides in Δ ADC equal the three sides in ΔCBA,

then the two triangles are congruent by SSS theorem

∴ The missing reason in step 3 is SSS congruency theorem

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3 years ago

Read 2 more answers