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3 years ago

Lana had 8 4/6 cups of flour. If she used 6 1/6 cups of flour, how much flour did she have left?

Mathematics

1 answer:

CaHeK987 [17]3 years ago

6 0

Answer:

2 3/6 or 2 1/2

Step-by-step explanation:

8 4/6 - 6 1/6 = 2 3/6

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Leeza is making labels in the shape of parallelograms each label has an area of 18 square centimeters and a base of 6 centimeter

Alenkinab [10]

Answer:

3cm

Step-by-step explanation:

A parallelogram is quadrilateral that has two pairs of parallel sides. The opposite sides equal in length

Area of a parallelogram = base x height

18cm² = 6cm x height

height = 18cm² / 6cm = 3cm

5 0

2 years ago

If you need 8 oz of chocolate chips to make 1.6 lb of cookie dough how many ounces of chocolate chips will you need to make 7 lb

iren [92.7K]

Answer:

3.5 Oz of chocolate

Step-by-step explanation:

1.6 lb of cookie dough is made from chocolate of 8 Oz

1 lb will be made by 8/ 1.6 = 0.5 Oz of chocolate

Therefore

7lb of cookie dough will be made from 7 * 0.5= 3.5 Oz of chocolate/

6 0

3 years ago

hannah's school hosted a book donation. there are 150 students at her school, and they donated b books! hannah donated 3 times a

MArishka [77]

3b=150 should be the answer.

8 0

2 years ago

Read 2 more answers

Charlotte reads 8 1/3 pages of a book in 10 minutes. What is her average reading rate in pages per minute?

sukhopar [10]

$8\frac{1}{3} = \frac{25}{3}$

25/3 pages of a book in 10 minutes

Multiply both numbers by the reciprocal of 10, which is 1/10

$\frac{25}{3} \times\frac{1}{10} = \frac{25}{30}=\frac{5}{6}$

$10\times\frac{1}{10}= 1$

So, Charlotte reads 5/6 pages of a book in 1 minute.

8 0

3 years ago

Can anyone help me about question 2

madreJ [45]

9514 1404 393

Answer:

3(4/3)^2543

Step-by-step explanation:

Using logarithms base 2, we have ...

$(a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}$

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

$\log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}$

and the 2544th term is ...

$\boxed{\log_2{a_{2544}}=3\left(\dfrac{4}{3}\right)^{2543}}$

8 0

2 years ago