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Alik [6]
4 years ago
11

(a) Find the remainder when 15! is divided by 17. (b) Find the remainder when 2(26!) is divided by 29, Thatermine whether 17 is

a prime by deciding whether 16! = -1
Mathematics
1 answer:
dlinn [17]4 years ago
4 0

Answer:

Step-by-step explanation:

a) We have 15! as the product of 1 to 15 natural numbers.  Since 17 is prime there will be no factor common to these

By actual division we find

15! (mod 17) =16

From this we deduce

even 16! mod 17 = 16 = -1

According to Wilson theorem

(17-1)! = -1 mod 17

Thus verified 17 is prime

Hence 15! (mod 17) =-1=16

-----------------------

b) 2(26!) is divided by 29

Since 29 is prime

(29-1)! = -1 mod 29

28! = -1 mod 29 = 28

When divided this gives 25 as remainder

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A notebook has a perimeter of 36 inches. It’s area is 80 square inches. What are the dimensions of the notebook
earnstyle [38]
Let's call he width of the notebook w and the length l

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7 0
4 years ago
Suppose c is inversely proportional to the square of d. If c=6 when d=3⁢, find the constant of proportionality and write the for
NemiM [27]

Answer:

The constant of proportionality is 54.

k = 54

c as a function of d:

c(d) = \dfrac{54}{d^2}

c(7) = \dfrac{54}{49}

Step-by-step explanation:

We are given the following in the question:

c is inversely proportional to the square of d.

\Rightarrow c\propto \dfrac{1}{d^2}\\\\\Rightarrow c = \dfrac{k}{d^2}\\\\\text{where k is constant of proportionality}

When c = 6, d = 3.

Plugging the values, we get,

6 = \dfrac{k}{3^2}\\\\\Rightarrow k = 6\times 3^2 = 54

Thus, the constant of proportionality is 54.

c as a function of d can be written as:

c(d) = \dfrac{54}{d^2}

We have to find value of c when d = 7.

Putting values, we get,

c(7) = \dfrac{54}{(7)^2}=\dfrac{54}{49}

is the required value of c.

4 0
3 years ago
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