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Lyrx [107]
3 years ago
10

jimmy raised $412.50 selling barbeque for a local chairity fundraiser. if he charged $7.50 for per pound of barbeque, how many p

ounds of babrbeque did jimmy sell?
Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

Step-by-step explanation:

You first have to divide $412.50 ( the total) by $7.50 (the pounds)

Then, you will get an answer of 55

So, JImmy sold 55 pounds of barbeque total

Hope this helps :)

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4x^2 + 36 / 4x × 1 / 5x
stich3 [128]
Given with a polynomial 4X² + 36/4X *1/5X, we can combine terms with the same power. First, let us perform multiplication of the 2nd and 3rd terms such as the given become 4X² + 36/20X². Then, we can reduce 36 and 20 by 4 and the result is 4X² + 9/5X². We can now proceed combining the terms since they have same power and result will be same as below:
(20X^4 + 9)/5X²
3 0
2 years ago
PLZ HURRY IT'S URGENT!!!!!
Arte-miy333 [17]

the ratio that is equal to 10:85 is 20:170 because if you multiply both sides by two you get 20:170

7 0
3 years ago
If the simple interest on $6,000 for 3 years is $1,620, then what is the interest rate?
Volgvan

Answer:

Interest rate: 9%

Step-by-step explanation:

Using the simple interest formula: A=P(1+rt)

A=Final amount

P=Principal amount

r=rate

t=time (years)

We just need to put in the information we have from the question and solve for r.

7,620=6000(1+r3)

7,620/6000=1+r3

1.27=1+r3

0.27=r3

r=0.09

r=9%

3 0
2 years ago
What is the product of the polynomial (7x+7) (x+2)
kolbaska11 [484]

Answer: 7x^2+21x+14

Step-by-step explanation:

(7x+7)(x+2)

Multiply each term in the first parentheses by each term in the second parentheses (FOIL)

7x×x+7x×2+7x+7×2

↘ ↙

7x×x calculate product

7x^2+7x×2+7x+7×2

↘ ↙

7x×2 calculate product

7x^2+14x+7x+7×2

↘↙

7×2 multiply numbers

7x^2+14x+7x+14

↘ ↙

21x collect like terms

7x^2+21x+14 is your end result.

3 0
3 years ago
Hi, I am new to this website :) I'm currently taking an online trig class on De Moivre's theorem and I don't understand it at al
Vladimir [108]
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.

For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes

[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))] 

it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.

For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)

[2^6(cos(40*6))+isin(40*6)],

[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)

And the answer is -32 -32 √3 i

Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i

7 0
3 years ago
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