$5+\frac{2}{p}=\frac{17}{p};\ p\neq0\\\\\frac{5p}{p}+\frac{2}{p}=\frac{17}{p}\\\\\frac{5p+2}{p}=\frac{17}{p}\iff5p+2=17\\\\5p=17-2\\\\5p=15\ /:5\\\\p=3$

5 0

3 years ago

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2x-y=5<br>2x-2y=4<br><img src="https://tex.z-dn.net/?f=2%20%5Ctimes%20%20-%20y%20%3D%205%20%5C%5C%202%20%5Ctimes%20%20-%202y%20%

d1i1m1o1n [39]

$\left\{\begin{array}{ccc}2x-y=5\\2x-2y=4&|\cdot(-1)\end{array}\right\\\underline{-\left\{\begin{array}{ccc}2x-y=5\\-2x+2y=-4\end{array}\right}\ \ \ \ |add\ both\ sides\\.\ \ \ \ \ \ \ \ y=1\\\\substitute\ the\ value\ of\ y\ to\ first\ equation\\\\2x-1=5\ \ \ |+1\\2x=6\ \ \ |:2\\x=3\\\\\left\{\begin{array}{ccc}x=3\\y=1\end{array}\right$

7 0

3 years ago