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garik1379 [7]
3 years ago
12

Question 1

Mathematics
1 answer:
goldenfox [79]3 years ago
4 0

Let t rep tail and h rep head

First tose= h or t

Second tose= h or t

Third tose= h or t

Counting the head and tail together

Then t= 3 and h=3

According to The formulae

3/6= 1/2

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Find x<br><br><br>A) 12<br><br>B) 13 <br><br>C) 11<br><br>D) 10
Soloha48 [4]

We know that the sum of arc ND and arc ML divided by 2 is equivalent to 6x + 23.

Thus, we can form an equation:

6x + 23 = (11x + 8 + 3x + 14)/2

Simplify:

6x + 23 = (14x + 22)/2

Simply again:

6x + 23 = 7x + 11

Subtract 6x from both sides:

23 = x + 11

Subtract 11 from both sides

x = 12

Option A, or x = 12

-T.B.

5 0
3 years ago
Which of these is equal to cos 47°?
tigry1 [53]
C tan 43 I think it right
4 0
3 years ago
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(1)Kamlesh brought a juice bottle of 5 litres. He drank 214 litres
Ainat [17]

Answer:

I think there is a typing error it should be 214 ml

Step-by-step explanation:

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hope it helps :)

5 0
3 years ago
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sveticcg [70]

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8 0
3 years ago
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On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly population (Drosophila) wi
Ket [755]

Answer:

(a). 15

(b). 78

Step-by-step explanation:

Growth of the population of a fruit fly is modeled by

N(t) = \frac{600}{1+39e^{-0.16t} }

where t = number of days from the beginning of the experiment.

(a). For t = 0 [Initial population]

N(0) = \frac{600}{1+39e^{-0.16\times 0} }

       = \frac{600}{1+39}

       = \frac{600}{40}

       = 15

Initial population of the fruit flies were 15.

(b).Population of the fruit fly colony on 11th day.

N(11) = \frac{600}{1+39e^{-0.16\times 11} }

       = \frac{600}{1+39e^{-1.76} }

       = \frac{600}{1+39\times 0.172 }

       = \frac{600}{1+6.71}

       = \frac{600}{7.71}

       = 77.82

       ≈ 78

On 11th day number of fruit flies colony were 78.

3 0
4 years ago
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