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yan [13]
3 years ago
12

A toy store had 3 boxes that weighed a total of 28 kilograms.how much did each box weigh

Mathematics
2 answers:
QveST [7]3 years ago
4 0

Answer:

Step-by-step explanation:

28/3

9.333333333333333

andrey2020 [161]3 years ago
4 0

Answer:

9.333333333333333333333333

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Z is equal to z because is z
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3 years ago
If f(x) = –5x – 4 and g(x) = –3x – 2, find (f – g)(x).
Murljashka [212]
Hello!

We'll start by simplifying the required formula. (f – g)(x) can be rewritten as the following:

f(x) – g(x)

Now insert any known values into the simplified formula above:

(-5x – 4) – (-3x – 2)

Eliminate the parentheses by simplifying:

-5x – 4 + 3x + 2

Combine like terms:

-2x – 2

We have now proven that (f – g)(x) is equal to (-2x – 2).

The correct answer is C.

I hope this helps!
7 0
3 years ago
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First to answer correctly gets brainliest
Gala2k [10]

Answer:

It's C -3,2 and 5 only

Step-by-step explanation:

5 0
3 years ago
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A transformation will......... have a number
MAXImum [283]

Answer: A transformation will <u><em>Sometimes</em></u> have a number

Step-by-step explanation:

7 0
3 years ago
Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
2 years ago
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