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serious [3.7K]
2 years ago
9

Select the algebraic expression(s) that represents this situation: Tamiya went to the store and bought 4 shirts that cost (n) do

llars each.
Mathematics
1 answer:
Natali [406]2 years ago
6 0

Answer: not sure if this is finished but i would say 4n

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A. lower quartile is 3 and upper quartile is 8

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Multiply by the conjugate and simplify
3/17 - 5i/17

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T divided by -4 equals nine
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Which pair of number has the least common multiple of 12
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3 and 4.

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3 years ago
Wholemark is an internet order business that sells one popular New Year greeting card once a year. The cost of the paper on the
erma4kov [3.2K]

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

                                = $0.05 + $0.15

                                = $0.20

Compute the total demand as follows:

Total demand = Mean × n

                       = 2000 × 4

                       = 8000

Compute the standard deviation of total demand as follows:

SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

         = $2.15 - $0.20

         = $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}

                               =\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907

Use Excel's NORMSINV{0.907} function to find the Z-score.

<em>z</em> = 1.322

Compute the optimal production quantity for the card as follows:

\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\

                                               =8000+(1.322\times 1000)\\=8000+1322\\=9322

Thus, the optimal production quantity is 9,322 cards.

8 0
2 years ago
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