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Anika [276]
3 years ago
9

What is the value of StartFraction negative 3 (7 + 5) over 3 squared EndFraction + 9 (2)?

Mathematics
2 answers:
Sati [7]3 years ago
9 0

Answer: C. 14

Step-by-step explanation:

-3(7) + -3(5)= -36

3^2= 9

9x2=18

-36/9= -4+18= 14

Trava [24]3 years ago
6 0

Answer:

C

Step-by-step explanation:

14

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Rewrite the equation without absolute value, thanks!
34kurt

Since x - 3 < 0 for -2 < x < 3, |x-3| = -(x-3)

Since x + 2 > 0 for -2 < x < 3, |x+2| = x+2

Since x - 5 < 0 for -2 < x < 3, |x-5| = -(x-5).

So y = -(x-3) + (x+2) -(-(x-5)) = 3 - x + x + 2 + x - 5 = x.

y = x, if -2 < x < 3.

4 0
3 years ago
What is the measure of arc EF in circle H?
ki77a [65]

41 degrees

I hope this helps

3 0
3 years ago
Find the points of intersection of the lines 10x−4y=2 and 2x+8y=7 without graphing.
Jet001 [13]

Answer:

x=\frac{1}{2},y=\frac{3}{4}

Step-by-step explanation:

Given:

10x-4y=2 ,2x+8y=7

To find: points of intersection of the given lines

Solution:

In substitution method, the system of equations is solved by expressing one variable in terms of another, as a result, removing one variable from an equation.

10x-4y=2 \\2(5x-2y)=2\\5x-2y=1\\5x=1+2y\\x=\frac{1+2y}{5}

Put x=\frac{1+2y}{5} in the equation 2x+8y=7

2x+8y=7\\2[\frac{1+2y}{5}]+8y=7\\ 2+4y+40y=35\\44y=35-2\\44y=33\\y=\frac{33}{44}\\ =\frac{3}{4}

Put y=\frac{3}{4} in the equation x=\frac{1+2y}{5}

x=\frac{1+2y}{5}\\=\frac{1}{5}[1+2(\frac{3}{4})]\\=\frac{1}{5}[1+(\frac{3}{2})]\\\\=\frac{1}{5}(\frac{2+3}{2}) \\\\=\frac{1}{5}(\frac{5}{2})\\\\=\frac{1}{2}

Therefore,

x=\frac{1}{2},y=\frac{3}{4}

5 0
3 years ago
-2 1/4 ÷ (-3 1/3) =<br><br> I will give brainliest
Vanyuwa [196]

Answer:

-2.09375

Step-by-step explanation:

4 0
4 years ago
What is the domain of the relation? {x| x = –4 , 0, 1, 2}. {x| x = –7, –6, 2, 3, 11}. {y| y = –4, 0, 1, 2}. {y| y = –7, –6, 2, 3
Katarina [22]

The domain of the relation can be expressed as: B. {x{x=-7, -6, 2, 11, 3}.

<h3>What is the Domain of a Relation?</h3>

The domain of a relation can be defined as all possible set of x-values or inputs that correspond to the respective y-values or outputs of the relation. The set of y-values or output, on the other hand, make the range of the relation.

In the relation given in the image above, the domain values are the inputs (x-values) while the range values are the outputs (y-values).

The set of x-values that make up the inputs in the given relation are: -7, -6, 2, 11, and 3.

We can state that -7, -6, 2, 11, and 3 are the domain of the relation, while the range of the relation include: 0, 1, -4, and 2.

Therefore, the domain of the relation can be expressed as: B. {x{x=-7, -6, 2, 11, 3}.

Learn more about the domain of a relation on:

brainly.com/question/2272412

#SPJ1

6 0
2 years ago
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