Answer:
the blanks for 54 are: 1,2,3,6
the blanks for 42 are: 1,2,3
HCF: 3
Step-by-step explanation:
the factors of each number are:
1 54 1 42
2 27 2 21
3 18 3 14
6 9
Answer:
1 gallon ever 5 minutes here is the fraction form if you need it for a graph 3/15 or 1/5
Step-by-step explanation:
if there is 3 gallons gone and it is constant then on gallon goes every 5 minutes 15/3=5
Lets day the original price of the dvd player was $100,
36% marked down means you pay $64x
64x = $41.60
100x = 100/54 x 41.60 = 4160/64 = #65.00 = original cost
similarly, stereo tuners = 100/78 x 69.42 = 6942/78 = $89 original cost
DVD = 65- 41.60 = $ 23. 40 less
Stereo = 89- 69.42 = $ 19.58 less
Diffrence is $ 3.82
so your answer is the dvd player price was reduced by $3.82 more than the stereo tuner.
Your answer is 1/4, -7/3,-4
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
