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Viefleur [7K]
3 years ago
6

What is the distance in y axis between each step in the graph of this function. y=int(3x)

Mathematics
1 answer:
MrRa [10]3 years ago
5 0
Anyway the distance is 1.
I give you the graphic of this function

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Solve the equatuon<br><br> x/2-(2/(x+1))=1<br><br> x=?
Snezhnost [94]

\frac{x}{2}-\frac{2}{x+1}=1

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]

Then shorten the fractions.

\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)

Distribute in all.

x^2+x-4=2x+2

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

x^2+x-4-2x-2=0\\x^2-x-6=0\\

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

(x-3)(x+2)=0\\x=3,-2

Thus, the answer is x = 3, -2

7 0
3 years ago
Use the following area model to multiply 29x97
alexandr402 [8]
The answer to 29×97 would be 2813
6 0
3 years ago
Construct a right angled triangle XYZ with 90 at angle Y, YZ=7.5cm and XY =6cm​
jeyben [28]

Answer:

1 draw a line of 7.5 cm YZ by scale

2 construct the 90 degree with the help of protecter

3 then cut arc of 6 cm on 90 degree of angle & mark as X

4 join X and Z by scale

6 0
3 years ago
What is the domain and range of the function f(x)=(1/5)^x
Luba_88 [7]

Answer:

domain: (- infinity, infinity) range:( 0, infinity)

Step-by-step explanation:

4 0
2 years ago
Solve the following pair of equations simultaneously.
Alchen [17]

Answer:

No solutions.

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination
  • Solving systems of equations by graphing
  • Expanding
  • Finding roots of a quadratic
  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

Step-by-step explanation:

<u>Step 1: Define systems</u>

2x - y = 9

4x² + 3y² - 2x + y = 16

<u>Step 2: Rewrite systems</u>

2x - y = 9

  1. Subtract 2x on both sides:                    -y = 9 - 2x
  2. Divide -1 on both sides:                          y = 2x - 9

<u>Step 3: Redefine systems</u>

y = 2x - 9

4x² + 3y² - 2x + y = 16

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                         4x² + 3(2x - 9)² - 2x + (2x - 9) = 16
  2. Expand:                                    4x² + 3(4x² - 36x + 81) - 2x + (2x - 9) = 16
  3. Distribute 3:                             4x² + 12x² - 108x + 243 - 2x + 2x - 9 = 16
  4. Combine like terms:                16x² - 108x + 234 = 16
  5. Factor GCF:                              2(8x² - 54x + 117) = 16
  6. Divide 2 on both sides:           8x² - 54x + 117 = 8
  7. Subtract 8 on both sides:        8x² - 54x + 109 = 0
  8. Define variables:                      a = 8, b = -54, c = 109
  9. Resubstitute:                            x=\frac{54\pm\sqrt{(-54)^2-4(8)(109)} }{2(8)}
  10. Exponents:                               x=\frac{54\pm\sqrt{2916-4(8)(109)} }{2(8)}
  11. Multiply:                                    x=\frac{54\pm\sqrt{2916-3488} }{16}
  12. Subtract:                                   x=\frac{54\pm\sqrt{-572} }{16}

Here we see that we start to delve into imaginary roots. Since on a real number plane, we do not have imaginary roots, there would be no solution to the systems of equations.

<u>Step 5: Graph systems</u>

<em>We can verify our results.</em>

8 0
3 years ago
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