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3 years ago

10

Write an absolute value equation that has the solution x=8 and x=18

1 answer:

saveliy_v [14]3 years ago

3 0

2.3 +.4=18 yeP THATS THE ANSWER ._.

You might be interested in

If sine of x equals square root of 2 over 2, what is cos(x) and tan(x)? Explain your steps in complete sentences.

kolbaska11 [484]

Sin x = square root (2) / 2

In order for us to get for cos x and tan x, first we need to know what
Hypotenuse, Adjacent, and Opposite sides.

sin x = opposite / hypotenuse.

adjacent = square root (hypotenuse^2 - opposite^2)
adjacent = square root (2^2 - square root(2)^2)
adjacent = square root (4 - 2)
adjacent = square root (2)

cos x = adjacent / hypotenuse
tan x = opposite / adjacent..

cos x = square root (2) / 2
tan x = square root (2) / <span>square root (2) = 1

So, </span>cos x = square root (2) / 2 and tan x<span> = 1</span>

7 0

3 years ago

What percent of 17 is 51?

Taya2010 [7]

Answer:

33%

Step-by-step explanation:

h steps:

Step 1: We make the assumption that 51 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=51$.

Step 4: In the same vein, $x\%=17$.

Step 5: This gives us a pair of simple equations:

$100\%=51(1)$.

$x\%=17(2)$.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{51}{17}$

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{17}{51}$

$\Rightarrow x=33.33\%$

Therefore, $17$ is $33.33\%$ of $51$.

4 0

2 years ago

Read 2 more answers

Eight less than three times a number is -23

Alenkasestr [34]

Answer: 10 is your answer bud ❤

4 0

3 years ago

Solve the rational function of (check image) and check for extraneous solutions

Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

$\frac{5}{x}=\frac{4x+1}{x^2}$

Solving the rational function

$\frac{5}{x}=\frac{4x+1}{x^2}$

Apply fraction across multiply: if $\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5x^2=x\left(4x+1\right)$

Subtract x(4x+1) from both sides

$5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)$

Simplify

$5x^2-x\left(4x+1\right)=0$

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$x=0\quad \mathrm{or}\quad \:x-1=0$

Thus, the solution to the equation is:

$x=0,\:x=1$

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0

3 years ago

You and six friends play a game where each person writes down his or her name on a scrap of paper, and the names are randomly di

Vanyuwa [196]

It would be 1/7 chance cause there are 7 people total but you have the 1 chance that you are going to get your own name

7 0

3 years ago