Please help, theres a picture

Mathematics

2 answers:

Katarina [22]3 years ago

4 0

Y= 15/x

you just have to substitute the x values

kiruha [24]3 years ago

3 0

Answer:

I think it is y equals to 15x

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| 5x - 3(x - 6) = 5x - 3x - 2x - 18 = 2 2x = 20 X = 10

MissTica

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3 years ago

Math question down below

MakcuM [25]

Answer:

B. 0.583

Step-by-step explanation:

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4 years ago

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Colin needs to borrow $1,500 for car repairs. How much interest will he pay if the rate is 4.9% and he has 125 days to repay the

Pachacha [2.7K]

For the answer to the question above, I'll use one-time computing.
Interest = Principal * rate * (loan duration/time unit) 
= $1500 * 4.9% * (125 days/365 days) 
Normally, a bank or accountant WOULD NOT use your method of rounding in the middle of the calculation but rather would round the final result. This is the normal way to handle all such mathematical processes. However, for your question, 
= $1500 * 4.9% * 0.34 
= $24.99 

If you don't do the rounding in the middle of the calculation, the answer is $25.17.
I hope this helps.

5 0

3 years ago

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The gas tank of a car is filled with a nozzle that discharges gasoline at a constant flow rate. Based on unit considerations of

Cloud [144]

Answer:

It is going 84.12s = 1 minute and 24.12 seconds to fill the tank.

Step-by-step explanation:

The filling time of a gas tank can be given by a first order function in this format:

$F(t) = V - r*t$

In which $F(t)$ is the current amount of fuel in the tank(in L), $V$ is the volume of the tank(in L), $r$ is the discharge rate of the tank(in L/s) and t is the time in seconds.

Finding the values of the parameters:

The tank is completly empty, so $F(t) = 0$ .

The volume of the tank is 14 gallons. However, the problem states that the volume of the tank is measured in liters.

Each gallon has 3.78L.

So $V = 14*3.78 = 53L$

The discharge rate for the gas is 38.0 l/min. However, the problem states that the discharge rate is in L/s. So, to find the value of r, we solve the following rule of three.

38 L - 60s

r L - 1s

$60r = 38$