Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
Ur question is ununderstable
Step-by-step explanation:
Answer:
10.5 in
Step-by-step explanation:
Given
Required
Find length AC
The question is not detailed enough; so, I'll assume that b represents line AC.
Having said that;
We start by multiplying both sides by b
Divide both sides by tan(55)
Find tan(55)
<em>(Approximated)</em>
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Length AC is 10.5
Answer:
$1350
Step-by-step explanation:
Percentage commision earned = 10%
Amount needed to pay for concert = $135
Hence, total sales for the week must be :
Let total sales = x
10% of total sales = $135
10/ 100 * x = $135
0.1x = $135
x = $135 / 0.1
x = $1350
Answer:
-3
Step-by-step explanation:
1.5x + 1.3x = -8.4
2.8x = -8.4
x=-3
