X^2+y^2=36
y=(x-6)
substitute y in first equation
x^2+(x-6)^2=36
x^2+x^2-12x+36=36
simplify and factor
2x(x-6)=0
so x=0, x=6
Answer:
Andrew has 9 cars
Step-by-step explanation:
Let's start by defining what our unknowns are and how to name them:
For the number of cars Andrew has: let's use the letter A
For the number of cars Luke has: let's use the letter L
Not write the first sentence in mathematical terms:
"Luke has 4 more than triples the number of cars that Andrew has."
L = 3 * A + 4
The second phrase results on a very simple equation since it just states the number of cars that Luke has:
L = 31
Now we can combine these two equations by replacing the variable "L" in the first equation with the second equation and then solve for A:
L = 3 * A + 4
31 = 3 * A +4
31 - 4 = 3 * A
27 = 3 * A
A = 27/3
A = 9
Therefore, Andrew has 9 cars.
Times bottom equation by 3 and top by 2 to get the same coefficient of x
6x-6y=60
6x+3y=33
Minus the bottom by the top
-9y=27
y=-3
substitute this in to one of the equations
2x -3 = 11
add 3 to both sides
2x=14
x=7
Answer:
Below.
Step-by-step explanation:
f(x)=3x^2-6x-45/x^2-5x
= 3x^2-6x-45 / (x(x - 5))
The denominator is zero when x - 0 and x = 5.
So there will be a vertical asymptote at x = 0 and a hole at x = 5.
If we do the division we get f(x) = 3 remainder 9x - 45
so there will also be a horizontal asymptote where x = 3.
Answer:
18750
Step-by-step explanation:
