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Dennis_Churaev [7]
3 years ago
12

At school, the maximum number of students that can be in a classroom is 21. If there are 16 students signed up for the geometry

class​, how many more students can join the class?
Mathematics
1 answer:
nalin [4]3 years ago
7 0

Step-by-step explanation:

Simple

We will subtract

21 - 16 = 5

So 5 more students can join the class

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The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

                   is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

                   \frac{A+B+C+D+E}{5} =30.

On multiplying both side by 5.

                       A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

  Then :  1 +2+3+4+E =150

On simplification  10+E =150

On subtraction both side by 10 we get

                      E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.


6 0
3 years ago
Please help I literally don’t understand this at all
mel-nik [20]

Answer:

x=13 y=10 z=3 d) 260

Step-by-step explanation:

vertex angles are congruent so you can set them equal to each other and solve

and then a straight like adds up to 180 so 180-(7(x-3)+5y)= your missing angle and then that angles is congruent to its opposite so 2(5z+15)=60

8 0
3 years ago
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)

7 0
2 years ago
LAST QUESTION ON MY TOPIC!!! PLEASE
nataly862011 [7]

Givens

<em><u>Slower car</u></em>

r = r

t = 12 hours

d = ?

<em><u>Faster car</u></em>

r = r + 20

t = 8 hours

d = ?

It doesn't matter what the exact distance is. You just have to know that the 2 distances are equal ie going to the mountains from his home is the same distance as going from the mountains to his home.

d = r * t

r * 12 hours = (r + 20)* 8 hours.   Remove the brackets on the right

r*12 = 8r + 20*8

r*12 = 8*r + 160

r*12 - 8r = 8r - 8r + 160

4r = 160

r = 40 miles / hour

=================

Slower Ride determines the distance.

d = r*t

d = 40 * 12

d = 480

Check

Use the faster rate (r + 20) = 40 + 20 = 60 mph

60 * 8 = 480. Both distances work out to be the same.

5 0
3 years ago
The slope of the line passing through the pair of points (-3,5) and (2,4)
Alik [6]
Whats the question here?
4 0
1 year ago
Read 2 more answers
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