Question

The sum of two numbers is 66. Two times the smaller number is 15 more than the larger number. What are the numbers?

Answer 1

Answer:

27 and 39.

Step-by-step explanation:

Let x be the smaller number and y be the larger number.

It is given that sum of two numbers is 66.

$x+y=66$

$y=66-x$        .... (1)

Two times the smaller number is 15 more than the larger number.  

$2x=15+y$         ... (2)

From (1) and (2) we get

$2x=15+(66-x)$  

$2x=81-x$  

$2x+x=81$  

$3x=81$

Divide both sides by 3.

$x=27$

Substitute x=27 in equation (1).

$y=66-27$

$y=39$

Therefore, the numbers are 27 and 39.

Answer 2

Here is the set up:

Let x and y be the two numbers with x the smaller and y the larger number.

x + y = 66

2x = y + 15

We have two equations in two unknowns.

Take it from here.