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Alika [10]
2 years ago
14

Rectangle WXYZ has vertices at W(−6, 1) , X(−1, 6) , Y(2, 3) , and Z(−3, −2) .

Mathematics
1 answer:
Alborosie2 years ago
4 0

The perimeter of the rectangle WXYZ that has vertices at W(−6, 1) , X(−1, 6) , Y(2, 3) , and Z(−3, −2) is 22.62 units.

<h3>What is rectangle?</h3>

It is defined as the two-dimensional geometry in which the angle between the adjacent sides are 90 degree. It is a type of quadrilateral.

We have a rectangle WXYZ has vertices at W(−6, 1) , X(−1, 6) , Y(2, 3) , and Z(−3, −2) .

Using the distance formula:

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Calculate the distance WX between (-6,1) and (-1,6)

WX = 7.07

The distance XY between (-1,6) and (2,3)

XY = 4.24

The distance YZ between (2,3) and (-3,-2)

YZ = 7.0

The distance ZW between (-6,1) and (-3,-2)

ZW = 4.24

Perimeter of the rectangle =   7.07+ 4.24 + 7.07 + 4.24 = 22.62 units

Thus, the perimeter of the rectangle WXYZ that has vertices at W(−6, 1) , X(−1, 6) , Y(2, 3) , and Z(−3, −2) is 22.62 units.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

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