Answer:
2/4 +6/8 =5/4
Step-by-step explanation:
<u>Answer:</u>
$6.00
<u>Step-by-step explanation:</u>
To solve this problem, we have to construct two separate equations for each family, and then use any of the methods for solving simultaneous equations.
Let's consider <em>h </em>to represent the cost of 1 hot dog, and <em>w </em>to mean the cost of 1 water bottle.
• For the first family:

We can rearrange the equation to make <em>w</em> the subject:
⇒ 
⇒ 
• For the second family:

Since we have previously obtained an expression for <em>w</em> in terms of <em>h</em>, we can substitute that expression for <em>w</em> in the above equation, and then solve for <em>h</em>:
⇒ 
⇒ 
⇒
[Multiplying both sides of the equation by 3]
⇒ 
⇒ 
⇒ 
∴ The price of one hot dog is $6.00.
Answer:
(6y - 1)(6y + 1)
Step-by-step explanation:
To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square is the product of the difference of the number and the sum of the numbers.
Such that
a² - b² = (a - b) (a + b)
Hence 36y² - 1
= 6²y² - 1²
= (6y)² - 1²
= (6y - 1)(6y + 1)
Perimeter of rectangle = length + length + width + width
To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14
Rectangle with perimeter 12
Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3
Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have
Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have
The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12
length = 4 and width = 2
length = 5 and width = 1
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Rectangle with perimeter of 14
Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14
Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14
Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14
We can have 3 different combinations of length and width