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Tema [17]
3 years ago
13

Factor this expression completely. 36y2 - 1

Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0
36y^{2}-1= (6y-1)(6y+1)
shtirl [24]3 years ago
5 0

Answer:

(6y - 1)(6y + 1)

Step-by-step explanation:

To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square  is the product of the difference of the number and the sum of the numbers.

Such that

a² - b² = (a - b) (a + b)

Hence 36y² - 1

= 6²y² - 1²

= (6y)² - 1²

= (6y - 1)(6y + 1)

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Given the data: 136, 150, 119, 150, 125, 143.<br> Find the range.
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Let $f(x)$ be a function defined for all positive real numbers satisfying the conditions $f(x) &gt; 0$ for all $x &gt; 0$ and $f
algol [13]
Suppose we choose x=1 and y=\dfrac12. Then

f(x-y)=\sqrt{f(xy)+1}\implies f\left(\dfrac12\right)=\sqrt{f\left(\dfrac12\right)+1}\implies f\left(\dfrac12\right)=\dfrac{1+\sqrt5}2


Now suppose we choose x,y such that

\begin{cases}x-y=\dfrac12\\\\xy=2009\end{cases}


where we pick the solution for this system such that x>y>0. Then we find

\dfrac{1+\sqrt5}2=\sqrt{f(2009)+1}\implies f(2009)=\dfrac{1+\sqrt5}2

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3 years ago
Read 2 more answers
8. Daren and Josh are pretty good free throw shooters. Daren makes 75% of the
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Answer:

B) Approximately normal, with mean -0.05 and standard deviation 0.083

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Pls help this is confusing :/
Aleksandr [31]

The coordinates of triangle U'V'W' include U'(8, 3), V'(4, -8) and W'(-8, -6) and this is represented by graph A shown in the image attached below.

<h3>What is a transformation?</h3>

A transformation can be defined as the movement of a point on a cartesian coordinate from its original (initial) position to a new location.

<h3>The types of transformation.</h3>

In Geometry, there are different types of transformation and these include the following:

  • Dilation
  • Reflection
  • Rotation
  • Translation

Based on the information provided, triangle UVW would be rotated counterclockwise through an angle of 270 degree at origin to produce triangle U'V'W', we have:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]

Therefore, the image of triangle UVW would be given by this matrix:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right] \left[\begin{array}{ccc}-3&8&6\\8&4&-8\end{array}\right]

Image = \left[\begin{array}{ccc}8&4&-8\\3&-8&-6\end{array}\right]

Based on the image above, we can logically deduce that the coordinates of triangle U'V'W' include U'(8, 3), V'(4, -8) and W'(-8, -6) and this is represented by graph A shown in the image attached below.

Read more on transformations here: brainly.com/question/12518192

#SPJ1

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Answer would be <span>6.
i've done this one before.</span>
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