All categories

3 years ago

Factor this expression completely. 36y2 - 1

Mathematics

2 answers:

Gennadij [26K]3 years ago

7 0

$36y^{2}$ -1= (6y-1)(6y+1)

shtirl [24]3 years ago

5 0

Answer:

(6y - 1)(6y + 1)

Step-by-step explanation:

To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square is the product of the difference of the number and the sum of the numbers.

Such that

a² - b² = (a - b) (a + b)

Hence 36y² - 1

= 6²y² - 1²

= (6y)² - 1²

= (6y - 1)(6y + 1)

You might be interested in

I need to know the square root answer of this problem simplified

Irina18 [472]

12 sqrt3 * 2 sqrt2 * 3

= 24 sqrt6 * 3

= 72 sqrt6 answer

4 0

3 years ago

Just b I need to know, I need explanation also.

Nastasia [14]

Answer:

$\implies \: 2.6851 \text{ \: ft}$

$\\$

Step-by-step explanation:

$\boxed{\boxed{ \blue\bigstar \red{ \bold{ \: \: math \: \: }} \blue\bigstar}}$

$\pink{\implies = \sqrt{ {36.1}^{2} - {36}^{2}} }$

$\orange{ \implies = \sqrt{1303.21} - 1.296}$

$\green{ \implies = \sqrt{7.21} }$

$\red{ \implies = 2.6851 \: \text{ft}}$

4 0

3 years ago

Find the y-intercept from the line passing through (1, 3) and having slope m=2.

Troyanec [42]

Answer:

The y intercept is 1

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 2x+b

Substitute the point into the equation and solve for y

3 = 2(1)+b

3 =2+b

1 = b

The y intercept is 1

8 0

3 years ago

Read 2 more answers

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units

ad-work [718]

Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}$

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0

3 years ago

What is the solution to the system of equations below?

disa [49]

The solution to the system of equation are x=2, y=0, z=6

<h3>System of equations</h3>

System of equations are equations that contains unknown variables.

Given the equations

3x+y+2z=8

8y+6z=36

12y+2z=12

From equation 2 and 3

8y+6z=36 * 1

12y+2z=12 * 3

______________

8y+6z=36

36y+6z= 36

Subtract

8y - 36y = 36 - 36

-28y =0

y = 0

Substitute y = 0 into equation 2

8(0)+6z=36

6z = 36

z = 6

From equation 1

3x+y+2z =8

3x + 0 + 2(6) = 8

3x = 8 - 12

3x = 6

x = 2

Hence the solution to the system of equation are x=2, y=0, z=6

Learn more on system of equation here: brainly.com/question/14323743

#SPJ1

3 0

1 year ago