Answer:
![(-7,4]\text{ or }\{x|-7](https://tex.z-dn.net/?f=%28-7%2C4%5D%5Ctext%7B%20or%20%7D%5C%7Bx%7C-7%3Cx%5Cleq%204%5C%7D)
Step-by-step explanation:
The domain is the span of x-values covered by the function.
From the graph, we can see that the graph covers all the x-values from x=-7 to x=4.
However, note that closed and open circles. There is an open circle at x=-7, which means that the domain excludes x=-7. However, the circle at x=4 is closed, meaning it is included in the domain.
Therefore, the domain is, in interval notation:
![(-7,4]](https://tex.z-dn.net/?f=%28-7%2C4%5D)
We use parentheses on the left because we do not include -7. And we use brackets on the right because we <em>do </em>include the 4.
And in set notation, this is:
The external angle is suplementary to the internal angle close to it. We also know that the sum of all the internal angles of the triangle are equal to 180 degrees, this means that the angle "a" is suplementary to the sum of the angles "b" and "c". Through this logic, we can conclude that since:
Then we can conclude that:
Therefore the statement is true, the exterior angle is equal to the sum of its remote interior angles.
Let's use an example:
On this example, the external angle is 120 degrees, therefore the sum of the remote interior angles must also be equal to that. Let's try:
The sum of the remote interior angles is equal to the external angle.
I am still learning, and am most likely incorrect.
I believe you remove the 3's since their not needed, and do this:
2x = 4x + 6 - (2x)
so then just ignore "x" and do this:
2 = 4 + 6 - 2
2 = 10 - 2
2 = 8
x = 8
To find the surface area of the open net, you’ll have to find the area of the faces
So, since there are 6 boxes you’ll have to find the area of the faces and add it up to find the surface area
10x4=40x4=160
3x4=12x2=24
160+24=184
Hope this helps ;)
Answer:
The Answer is C. false; m =-2 or m=2
Step-by-step explanation:
This is because:
2*2=4 being 4+6=10 Making 2 true, but
-2*-2= 4 as well making it 4+6=10, Making -2 true as well.
