Step-by-step explanation:
anything greater than 195.
Nani!? Omae wa mou shindeiru
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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Answer:
A system of the equation of a circle and a linear equation
A system of the equation of a parabola and a linear equation
Step-by-step explanation:
Let us verify our answer
A system of the equation of a circle and a linear equation
Let an equation of a circle as
..........(1)
Let a liner equation Y = x ............(2)
substitute (2) in (1)

so Y =
so the two solution are (
)
A system of the equation of a parabola and a linear equation
Let equation of Parabola be 
and linear equation y = x
substitute

Y = 0,1
so the two solutions will be (0,0) and (1,1)