Let s represent the short side of the triangle. The long sides of the triangle are each s+1, and the triangle's perimeter is
... s + (s+1) + (s+1) = 3s+2
The length of one side of the square is s-2, and its perimeter is 4 times that, 4(s-2) = 4s-8. The square and triangle have the same perimeter, so
... 3s+2 = 4s-8
... 10 = s . . . . . . . . add 8-3s to both sides
The length of the shorter side of the triange is 10 units.
Answer:
x=1
y=4
(1,4)
Step-by-step explanation:
TO SOLVE FOR X:
1. Substitute y=x+3 into the equation. This should look like this:
3x+5(x+3)=23
2. Use the distributive property.
3x+5x+15=23
3. Simplify:
8x+15=23
4. Subtract 15 from both sides. It should now lool like this:
8x=8
5. Divide both sides by 8.
x=1
TO SOLVE FOR Y:
1. Take x and substitute into original statement:
3(1)+5y=23
2. Simplify:
3+5y=23
3. Subtract 3 from both sides:
5y=20
4: Simplify:
y=4
CHECK ANSWER:
y=x+3
1. Substitute your answers
4=1+3
2. Simplify
4=4
3. Check for Truth. Is 4=4?
Yes. So your final answer is:
x=1
y=4
(1,4)
For this case we have the following equation:

Where,
I: <span>the intensity of a given sound
I0: </span><span> the threshold of a hearing intensity
</span>Substituting values in the given equation we have:
<span />

<span />Rewriting the equation we have:
<span />

<span />Then, by properties of logarithm we have:
<span />

<span />Finally we have:
<span />

<span />
Answer:
T<span />
he intensity, in decibles, [I(dB)], when I=10^8(I0) is:
D.80
Answer:
5 and 12
Step-by-step explanation:
The mode of a data set is the entry which occurs most often
Given
5, 10, 12, 4, 6, 11, 12, 5
5 and 12 both occur twice, thus there are 2 modes 5 and 12
Answer:
It is a reflection of the y axis, with 2 units down. :)
Step-by-step explanation: