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3 years ago

If pp is inversely proportional to the square of qq, and pp is 24 when qq is 7, determine pp when qq is equal to 2.

Mathematics

1 answer:

dimulka [17.4K]3 years ago

6 0

Answer:

Let me know

Step-by-step explanation:

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3 years ago

Use a benchmark fraction to compare 7 10 ths and 5 12 ths. Explain how you found the answer

Oksanka [162]

I dont know what benchmark means but <em />I hope this works<em>. </em>First, multiply 7 10ths by the denominator of 12. 7/10 *12= 84/120.
Then multiply 5 12ths by 10. 5/12 *10=50/120. So, 7/10 > 5/12

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3 years ago

In the French test she scored 34 out of 50.

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3 years ago

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frosja888 [35]

(-6)-(+2)= -8

(-9)-(-8)= -17

(-6)-(+6)= -12

(-8)-(-8)= -16

(+5)-(+1)= 4

(+6)-(-2)= 8

(-3)-(+5)= -8

(-8)-(+5)= -13

(-9)-(-4)= -13

(+1)-(+3)= -2

(-3)-(+8)= -11

(+9)-(-4)= 13

(+8)-(-7)= 15

(-6)-(+3)= -9

(-3)-(+4)= -7

(-4)-(+3)= -7

(-6)-(+1)= -7

(+8)-(-8)= 16

(+1)-(+4)= -3

(+7)-(+9)= -2

(+5)-(-5)= 10

(+6)-(-9)= 15

(+7)-(-5)= 12

(+2)-(+1)= 1

(-6)-(+3)= -9

(+2)-(+9)= -7

(+1)-(+1)= 0

(-2)-(+3)= -5

(+3)-(+4)= -1

(+8)-(-9)= 17

8 0

3 years ago

Find a unit vector in the same direction as the given vector: v = −14.5i + 2.5 j.

Elis [28]

ANSWER

$- \frac{29}{866} \sqrt{866} i + \frac{5}{866} \sqrt{866} j$

EXPLANATION

The given vector is v = −14.5i + 2.5 j.

The magnitude of this vector is

$|v| = \sqrt{ {( - 14.5)}^{2} + {2.5}^{2} }$

$v| = \sqrt{ {( - 14.5)}^{2} + {2.5}^{2} }$

$v| = \sqrt{ 216.5} = \frac{ \sqrt{866} }{2}$

The unit vector in the direction of this vector is

$= \frac{v}{ |v| }$

$= - \frac{14.5}{ \frac{ \sqrt{866} }{2} } i + \frac{2.5}{ \frac{ \sqrt{866} }{2} } j$

$= - \frac{29}{866} \sqrt{866} i + \frac{5}{866} \sqrt{866} j$

7 0

3 years ago