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gizmo_the_mogwai [7]
2 years ago
7

F(x) = 3x+2 What is f(5)?

Mathematics
1 answer:
Artist 52 [7]2 years ago
6 0

Answer:

f(5)=17

Step-by-step explanation:

if,f(x)=3x+2

Then,f(5)=3*5+2

f(5)=17

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puteri [66]

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3 0
3 years ago
4 The width of a rectangular dance floor
Brilliant_brown [7]

Answer:

\boxed{\sf a. \ 6x + 5}

Given:

f(x) = -2x + 5

To Find:

f(-3x)

Step-by-step explanation:

\sf Evaluate \ f(x) \ by \ substituting \ in \ the \\ \sf value \ of \ x = -3x \ into \ f(x): \\ \sf f( - 3x) = -2( - 3x) + 5 \\ \\ \ \ \ \ \ \ \ \ \ \ \ \  \sf =  6x + 5

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4 years ago
Prove the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus. use the distance formula
riadik2000 [5.3K]
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D_{x} = \frac{-2b-2a}{2}=-b-a and D_{y}= \frac{2c+0}{2}=c. The coordinates of D is (-b-a, c)
E_{x} = \frac{-2b+2b}{2}=0 and E_{y}= \frac{2c+2c}{2}=2c. The coordinates of E is (0,2c)
Since we have the reflection in this graph, the coordinates of F is (b+a, c)
And the coordinates of G is (0,0).

Using the distance formula, we can find that 
DE= \sqrt{(-b-a)^{2}+ c^{2}}=\sqrt{(b+a)^{2} + c^{2}}
EF= \sqrt{(b+a)^{2} + c^{2} }
GF= \sqrt{(b+a )^{2} + c^{2} }
DG= \sqrt{(b+a)^{2}+ c^{2} 

Since all the sides are equal this completes our proof. Additionally, we can find the distances of EG and DF in order to show that the diagonals of this rhombus are not equal. So that it is not a square, but rhombus. 

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3 years ago
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Answer:

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