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3 years ago

Solve the equation 8.5 -1.2 x =6.7

2 answers:

8 0

The first thing you have to do is subtract 8.5 from both side to get -1.2x=-1.8

Then, you have to divide both sides by -1.2

The final answer would be x=1.5

Viefleur [7K]3 years ago

3 0

X = 1.5
8.5 - 1.2(1.5) = 6.7

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Anne earned $3 an hour baby-sitting, and $4 an hour working in the garden. Last week she did baby-sitting for 5 hours and garden

Dmitry_Shevchenko [17]

She needs 8 more dollars.
if you multiply 3 times 5 equals 15
and 4 times 3 equals 12
then add that which is 27
35 minus 27 is 8.

8 0

3 years ago

The value of x satisfying both the equations 4x – 5 = y and 2x – y = 3, when y = -1 is

schepotkina [342]

Answer:

x = 1

Step-by-step explanation:

4x-5=y

4x-5= -1

4x = -1+5

4x=4

x=1

2x-y=3

2x-(-1)=3

2x+1=3

2x= 3-1

2x= 2

x=1

since the two answers for x are the same therefore:

x = 1

4 0

4 years ago

Garth buys 24 kilograms of candy. He then repacks the candy into small bags of 34 kilogram each. How many bags does he pack? A.

LenaWriter [7]

<u>Corrected Question</u>

Garth buys 24 kilograms of candy. He then repacks the candy into small bags of 3/4 kilogram each. How many bags does he pack?

Answer:

C. 32 bags

Step-by-step explanation:

Total Weight of Bag bought =24 kilograms

Since Garth wants to repack the candy into small bags of 3/4 kg, we simply divide 24 by 3/4 to obtain the number of small bags.

$24 \div \dfrac{3}{4}= 24 X \dfrac{4}{3}\\=32$

There will be 32 small bags of 3/4 kg.

The correct option is C.

6 0

4 years ago

Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t) (in cm) as a function of time t (in s

xz_007 [3.2K]

Answer:

R (t) = 60 - 60 cos (6t)

Step-by-step explanation:

Given that:

R(t) = acos (bt) + d

at t= 0

R(0) = 0

0 = acos (0) + d

a + d = 0 ----- (1)

After $\dfrac{\pi}{12}$ seconds it reaches a height of 60 cm from the ground.

i.e

$R ( \dfrac{\pi}{12}) = 60$

$60 = acos (\dfrac{b \pi}{12}) +d --- (2)$

Recall from the question that:

At t = 0, R(0) = 0 which is the minimum

as such it is only when a is negative can acos (bt ) + d can get to minimum at t= 0

Similarly; 60 × 2 = maximum

R'(t) = -ab sin (bt) =0

bt = k π

here;

k is the integer

making t the subject of the formula, we have:

$t = \dfrac{k \pi}{b}$

replacing the derived equation of k into R(t) = acos (bt) + d

$R (\dfrac{k \pi}{b}) = d+a cos (k \pi)$ $= \left \{ {{a+d \ for \ k \ odd} \atop {-a+d \ for k \ even}} \right.$

Since we known a < 0 (negative)

then d-a will be maximum

d-a = 60 × 2

d-a = 120 ----- (3)

Relating to equation (1) and (3)

a = -60 and d = 60

∴ R(t) = 60 - 60 cos (bt)

Similarly;

For $R ( \dfrac{\pi}{12})$

$R ( \dfrac{\pi}{12}) = 60 -60 \ cos (\dfrac{\pi b}{12}) =60$

where ;

$cos (\dfrac{\pi b}{12}) =0$

Then b = 6

∴

R (t) = 60 - 60 cos (6t)

7 0

3 years ago

Just help me plssssssssss

Komok [63]

Answer:

The perimeter of triangle is 30ft.

Step-by-step explanation:

First you have to find the value of a using Pythogoras Theorem, a² + b² = c² where a and b is the sides and c is the hypotenuse :

${a}^{2} + {b}^{2} = {c}^{2}$

${a}^{2} = {c}^{2} - {b}^{2}$

$a = \sqrt{ {c}^{2} - {b}^{2} }$

Let b = 12,

Let c = 13,

$a = \sqrt{ {13}^{2} - 12 {?}^{2} }$

$a = \sqrt{25}$

$a = 5feet$

Next you have to find the perimeter of triangle by adding all the sides together :

$perimeter = 5 + 12 + 13$

$perimeter = 30feet$

7 0

3 years ago