How many $150,000 homes would the $1.2 trillion buy

Find the surface area of the triangular prism. Will mark brainliest!

klio [65]

Answer:

720 sq ft

Step-by-step explanation:

Formula:

2 B + P x H

3 0

3 years ago

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What is the range of y = sin-1x? [–1, 1] [0, π] left-bracket negative startfraction pi over 2 endfraction, startfraction pi over

soldi70 [24.7K]

The range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].

<h3>What is the range of the function?</h3>

Range of a function is the set of all the possible output values which are valid for that function.

The trigonometry function given in the problem is,

$y = \sin^{-1}x$

The above function can be written as,

$\sin y = x$

The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.

$-1\leq x\leq1$

This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,

$-\dfrac{\pi}{2}\leq x\leq\dfrac{\pi}{2}$

Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].

Learn more about the range of the function here;

brainly.com/question/2264373

7 0

3 years ago

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

2) x=16

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

x=16 is a solution

Then the solutions are x=0 and x=16

5 0

3 years ago

The purchase price of a camera is $84. The carrying case is 12% of the purchase price. Tax 6% of the subtotal. What is the total

ICE Princess25 [194]

Hi there! So, we know that the price of the camera is $84, and the carrying case is 12% of that price. Let's find the cost of the case. To find the cost of the carrying case, all you have to do is multiply the price of the camera by the percentage. 84 * 12% (0.12) is 10.08. The price of the carrying case is $10.08. Let's add that price to the price of the camera. 84 + 10.08 is 94.08. $94.08 is the purchase price, but we're not done. We must add the tax in to find the total price. We can add 100% to the tax rate of 6% to get 106% Adding 100% to the amount of tax helps us get straight to the total price. Multiply that by 94.08. 94.08 * 106% (1.06) is 99.7248 or 99.72 when rounded to the nearest hundredth. There. The total price of the purchase is $99.72.

4 0

4 years ago

(15+23)+7=15+(___+7)

konstantin123 [22]

23 hope this helps!!

6 0

3 years ago

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